Answer:
a. Leu-Ala-Arg-Phe-Val-Val-Lys
.
Explanation:
Hello.
In this case, considering the given data, we notice that the amino acid has a N-terminal Leu, that is why we first discard d. Moreover, considering the data (iii) and (v) we can infer that there are going to be two fragments by which it is possible to reason the proper sequence:
(iii): the amino acid has one section composed by Lys-Phe-Val-Val and another one by Ala, Arg, Leu that is why e is also discarded.
(v): the other two fragments are Ala, Arg, Leu, Phe, that is why b is discarded.
(iii) and (v): given the aforementioned fragments, we can combine them and therefore discard c, that is why the correct sequence is:
a. Leu-Ala-Arg-Phe-Val-Val-Lys
.
Best regards.
A : falling back to a it’s original lower state after being excited by fire.
Answer:
3.25 M
Explanation:
Number of moles = mass/ molar mass
mass of NaOH = 65 g
Molar mass of NaOH = 40 g/mol
Number of moles of NaOH = 65g/40 g/mol = 1.625 moles
Let us recall that;
n = CV
n = number of moles of solute
C = concentration of solution
V = volume of solution
C = n/V
n = 1.625 moles
V = 500/1000 L = 0.5 L
C = 1.625 moles/0.5
C = 3.25 M