Given the distance between the crest of one wave and the crest of the next wave, you can determine the?

A small, 3 kg weight is moved from 5 m from the ground to 8 m. What is the change in potential energy?

Ulleksa [173]

Answer: 88.2 J

Explanation: PE, OR Potential Energy, equals to mass gravity and height.

mass - 3kg

height - 3 because (8-5)

gravity is 9.8kg

so 3 times 3 times 9.8 = 88.2J

4 0

4 years ago

What is significant about the primary colors of pigments?

ASHA 777 [7]

A. They can be mixed together to make almost any other color.

Explanation:

The most significant thing about primary colors is that they can be mixed together to form any other colors. Primary colors are red, blue and green. These are the three primary colors of light.

Other colors can derived from primary colors when making pigments.
If the the three primary colors are mixed together, white color is produced.
Secondary colors are the other colors produced by combining any two primary colors of light.
Two colors the produce white when mixed are complementary colors.

Learn more:

Color vision brainly.com/question/5661389

#learnwithBrainly

8 0

3 years ago

A dime is placed in front of a concave mirror that has a radius of curvature R = 0.40 m. The image of the dime is inverted and t

andrew11 [14]

Answer:

distance between the dime and the mirror, u = 0.30 m

Given:

Radius of curvature, r = 0.40 m

magnification, m = - 2 (since,inverted image)

Solution:

Focal length is half the radius of curvature, f = $\frac{r}{2}$

f = $\frac{0.40}{2} = 0.20 m$

Now,

m = - $\frac{v}{u}$

- 2 = - $\frac{v}{u}$

$\frac{v}{u}$ = 2 (2)

Now, by lens maker formula:

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$

$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$

v = $\frac{uf}{u - f}$ (3)

From eqn (2):

v = 2u

put v = 2u in eqn (3):

2u = $\frac{uf}{u - f}$

2 = $\frac{f}{u - f}$

2(u - 0.20) = 0.20

u = 0.30 m

6 0

3 years ago

The drag force that resists the motion of a car traveling at 80 km h^- 1 is 300 N.

kobusy [5.1K]

The power require to keep the car traveling is 6,666 W.

The power of the engine at the given efficiency is 3,999.6 W.

<h3>What is Instantaneous power?</h3>

This the product of force and velocity of the given object.

The power require to keep the car traveling is calculated as follows;

P = Fv

$P = 300\ N \ \times \ \frac{80 \ kmh^{-1}}{3.6 \ km h^{-1}/m/s} \\\\
P = 300 \ N \times 22.22 \ m/s\\\\
P = 6,666 \ W$

The power of the engine at the given efficiency is calculated as follows;

$E = \frac{P_{out}}{P _{in}} \times 100\%\\\\
60\% = \frac{P_{out}}{6,666} \times 100\%\\\\
0.6 = \frac{P_{out}}{6,666} \\\\
P_{out} = 3,999.6 \ W$

Learn more about efficiency here: brainly.com/question/15418098

8 0

2 years ago

A car is driving around a banked curve, with the road surface at an angle of 10.0º. If the radius of curvature of the road is 30

IRISSAK [1]

Answer:

maximum speed 56 km/h

Explanation:

To apply Newton's second law to this system we create a reference system with the horizontal x-axis and the Vertical y-axis. In this system, normal is the only force that we must decompose

sin 10 = Nx / N

cos 10 = Ny / N

Ny = N cos 10

Nx = N sin 10

Let's develop Newton's equations on each axis

X axis

We include the force of friction towards the center of the curve because the high-speed car has to get out of the curve

Nx + fr = m a

a = v2 / r

fr = mu N

N sin10 + mu N = m v² / r

N (sin10 + mu) = m v² / r

Y Axis

Ny -W = 0

N cos 10 = mg

Let's solve these two equations,

(mg / cos 10) (sin 10 + mu) = m v² / r

g (tan 10 + μ / cos 10) = v² / r

v² = r g (tan 10 + μ / cos 10)

They ask us for the maximum speed

v² = 30.0 9.8 (tan 10+ 0.65 / cos 10)

v² = 294 (0.8364)

v = √(245.9)

v = 15.68 m / s

Let's reduce this to km / h

v = 15.68 m / s (1 km / 1000m) (3600s / 1h)

v = 56.45 km / h

This is the maximum speed so you don't skid

7 0

3 years ago