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kramer
3 years ago
5

What percentage of energy is available to organisms at each level of an energy pyramid?

Physics
1 answer:
Snowcat [4.5K]3 years ago
6 0
The percentage of energy available to each organism is always 10 percent . 
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how much voltage is in the primary coil if there are 3200 winding in the secondary coil 500 winding in the primary and 25v in th
Tema [17]

Answer:

Voltage in the primary winding of the coil is 3.9 V

Explanation:

As we know by the principle of transformer we have

\frac{V_s}{V_p} = \frac{N_s}{N_p}

here we know that

V_s = 25 volts

N_s = 3200

N_p = 500

now we have

\frac{25}{V_p} = \frac{3200}{500}

V_p = 3.9 Volts

7 0
3 years ago
How does water form in the clouds? Explain how
Aloiza [94]

When air rises in the atmosphere it gets cooler and is under less pressure. When air cools, it's not able to hold all of the water vapor it once was. Air also can't hold as much water when air pressure drops. The vapor becomes small water droplets or ice crystals and a cloud is formed.

I hope this helps you..

3 0
2 years ago
In a football game, a receiver is standing still, having just caught a pass. Before he can move, a tackler, running at a velocit
ivolga24 [154]

Answer:

m_{receiver}=115Kg*3.1/(1.6)-115Kg=107.8Kg    

Explanation:

The football players collide in a completely inelastic collision, in other words they have the same velocity after the collision, this velocity has a magnitude V=1.6m/s.

We need to use the conservation of momentum Law, the total momentum is the same before and after the collision, at the initial point the receiver does not have any speed

m_{tackler}*v_{tackler}=(m_{tackler}+m_{receiver})V     (1)

We solve in order to find the receiver mass:

m_{receiver}={m_{tackler}*v_{tackler}/V}-m_{tackler}    

m_{receiver}=115Kg*3.1/(1.6)-115Kg=107.8Kg    

5 0
3 years ago
What does a cell use to eliminate a substance that is too large to leave by diffusion?
zysi [14]
<span>a cell eliminates endocytosis.

</span>
6 0
3 years ago
A 2 kg object traveling at 5 m s on a frictionless horizontal surface collides head-on with and sticks to a 3 kg object initiall
Svetlanka [38]

Answer: (d)

Explanation:

Given

Mass of object m=2\ kg

Speed of object u=5\ m/s

Mass of object at rest M=3\ kg

Suppose after collision, speed is v

conserving momentum

\Rightarrow mu+0=(m+M)v\\\\\Rightarrow v=\dfrac{2\times 5}{2+3}\\\\\Rightarrow v=2\ m/s

Initial kinetic energy

k_1=\dfrac{1}{2}\times 2\times 5^2\\\\k_1=25\ J

Final kinetic energy

k_2=\dfrac{1}{2}\times (2+3)\times 2^2\\\\k_2=10\ J

So, it is clear there is decrease in kinetic energy . Thus, energy decreases and velocity becomes 2 m/s.

4 0
2 years ago
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