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DIA [1.3K]
3 years ago
10

What activities should you avoid to prevent static discharge while working on a computer?

Physics
1 answer:
nordsb [41]3 years ago
6 0
Dont where socks or stand on carpet while working on a computer, also dont set components on carpet.
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What describes the gravitational force from a planet
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8 0
3 years ago
Assume that the speed of light in a vacuum has the hypothetical value of 18.0 m/s. A car is moving at a constant speed of 14.0 m
Oksi-84 [34.3K]

Answer:

Observed time, t = 5.58 s  

Explanation:

Given that,

Speed of light in a vacuum has the hypothetical value of, c = 18 m/s

Speed of car, v = 14 m/s along a straight road.

A home owner sitting on his porch sees the car pass between two telephone poles in 8.89 s.

We need to find the time the driver of the car measure for his trip between the poles. The relation between real and observed time is given by :

T=\dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}} }

t is observed time.

t=T\times \sqrt{1-\dfrac{v^2}{c^2}} \\\\t=8.89\times \sqrt{1-\dfrac{14^2}{18^2}} \\\\t=5.58\ s

So, the time observed by the driver of the car measure for his trip between the poles is 5.58 seconds.

4 0
3 years ago
A roller coaster's velocity at the bottom of a hill is 35.0 m/s, 5.00 seconds later it reaches the top of the hill with a veloci
anyanavicka [17]

Answer:

5 m /s^2

Explanation:

Change in velocity = 35 - 10 = 25 m/s

change in time = 5 s

decelleration = 25/5 = 5 m/s^2

4 0
2 years ago
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egoroff_w [7]
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6 0
3 years ago
given the data 11.4, 11.3, 11.2 and 11.1 cm determine the average and its standard deviation using equation
Ostrovityanka [42]

Answer:

Average  \bar{x} = 11.25 cm

standard deviation = 0.129 cm

Explanation:

The data provided in the question is:

x₁ = 11.4 cm

x₂ = 11.3 cm

x₃ = 11.2 cm

x₄ = 11.1 cm

total number of data points, N = 4

Now, the average is calculated as:

Average \bar{x} = \frac{sum\ of\ all\ the\ data\ points }{number\ of\ data\ points}

substituting the values in the above formula we get,

Average  \bar{x} = \frac{11.4cm+11.3cm+11.2cm+11.1cm }{4}

Average  \bar{x} = 11.25 cm

Now the standard deviation is calculated as:

standard deviation = \sqrt\frac{\sum_{i=1}^{4} \left(x_i - \bar x \right )^2}{N-1}

substituting the values in the above equation we get,

standard deviation = \sqrt\frac{\left(11.4 - 11.25 \right )^2 + \left(11.3 - 11.25 \right )^2 + \left(11.2 - 11.25 \right )^2 + \left(11.1 - 11.25 \right )^2}{3}

or

standard deviation = 0.129 cm

5 0
3 years ago
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