Answer:
10.2 metres
Explanation:
Given that a ball is projected at an initial speed of 20.0 meter per second making an angle of 45.0 with horizontal. What is the maximum height it will reach?
Solution
To get the maximum height, let us use the formula
V^2 = U^2 sin^2ø - 2gH
At maximum height V = 0
U^2 sin^2ø = 2gH
Substitute all the parameters into the formula
20^2 ( sin 45 )^2 = 2 × 9.8 × H
400 × 0.5 = 19.6 H
Make H the subject of formula
H = 200 / 19.6
H = 10.204 metres.
Therefore, the maximum height reached by the projected ball is 10.2 metres.
Answer:
Because their properties like conductivity, electronic configuration and ionization lies in between the metals and nonmetals.
Explanation:
There are a total of six elements that fall in the category of semiconductors.
Namely these are boron, silicon, germanium, arsenic, antimony, and tellurium.
These elements look like metals i.e. are lustrous but do not conduct electricity so well like a metal does.
Their chemical behavior falls between that of metals and nonmetals. For example, the pure metalloids form covalent crystals like the nonmetals, but like the metals, they generally do not form mono-atomic anions.
Answer:
a)H=84.87 m
b)R=565.27 m
Explanation:
Given that
Speed of ball on earth
U=41.2 m/s
θ=31°
We know that
Maximum height in projectile motion given as
h=22.94 m
Range in projectile motion given as
r=152.77 m
Given that on distance planet ball moves 3.7 times far more as on earth.
So on the distance planet
The maximum height ,H=3.7 h
H= 3.7 x 22.94
H=84.87 m
The range on distance planet
R=3.7 r
R=3.7 x 152.77 m
R=565.27 m
