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3 years ago

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Chemistry

1 answer:

Firlakuza [10]3 years ago

4 0

Answer:

Q = 52668 J

Explanation:

Given data:

Amount of heat required = ?

Mass of water = 350 g

Initial temperature = 20°C

Final temperature = 56°C

Specific heat capacity of water = 4.18 J/g°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 56°C - 20°C

ΔT = 36°C

Q = 350 g× 4.18 J/g°C ×36°C

Q = 52668 J

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Write an equation that shows the formation of the iodide ion from a neutral iodine atom.

Dennis_Churaev [7]

In its elemental form, Iodine is a diatomic molecule in the gas phase. In the periodic table, Iodine is just right beside Xenon which is a stable element because it has no extra electrons. Thus, to conform to stability, Iodine must have to gain one more electron. That's why in its ionic form, its formula is I⁻. The reaction would be

I₂ → 2 I⁻

To achieve the Law of Definite Proportions from Dalton's Atomic Theory, we must balance the reaction. So in every neutral Iodine atom, 2 Iodide ions are formed.

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4 years ago

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How many grams of h2 are needed to produce 10.78 g of nh3?

balu736 [363]

Ammonia is formed by a reaction between hydrogen and nitrogen as shown by the equation below.
N2(g) + 3H2(g) = 2NH3(g)
1 mole of ammonia contains 17 g
Therefore 10.78 g of ammonia are equivalent to 10.78/17 = 0.6341 moles
The mole ratio of hydrogen to ammonia is 3 : 2
Therefore, moles of hydrogen used will be 0.6341 × 3/2 = 0.9512 moles
1 mole of hydrogen is equivalent to 2 g
Thus, the mas of hydrogen will be 0.9512 moles × 2 = 1.9023 g

6 0

4 years ago

3. A sample of krypton gas occupies 75.0 mL at 0.400 atm. If the temperature remained constant, what volume would the krypton oc

Kruka [31]

c) 29.8 mL

d) 5375 mL

e) $6.5\cdot 10^5 mL$

Explanation:

We can solve this problem by using Boyle's Law, which states that:

"For a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"

Mathematically:

$pV=const.$

where

p is the pressure of the gas

V is its volume

We can rewrite the formula as

$p_1 V_1 = p_2 V_2$

For the gas in this problem:

$p_1=0.400 atm$ is the initial pressure

$V_1=75.0 mL$ is the initial volume

$p_2=765 mmHg = 1.006 atm$ is the final pressure (using the conversion factor $1 atm = 760 atm$ )

Solving for V2, we find the final volume:

$V_2=\frac{p_1 V_1}{p_2}=\frac{(0.400)(75.0)}{1.006}=29.8 mL$

We can solve this part by using again the equation:

$p_1 V_1 = p_2 V_2$

Where in this case we have:

$p_1=0.400 atm$ is the initial pressure

$V_1=75.0 mL$ is the initial volume

$p_2=4.00 mmHg$ is the final pressure

Converting into atmospheres,

$p_2 = 4.00 mmHg \cdot \frac{1}{760 mmHg/atm}=0.0053 atm$

And solving for V2, we find the final volume:

$V_2=\frac{p_1 V_1}{p_2}=\frac{(0.400)(75.0)}{0.0056}=5357 mL$

As before, we use Boyles' Law:

$p_1 V_1 = p_2 V_2$

In this part we have:

$p_1=0.400 atm$ is the initial pressure of the gas

$V_1=75.0 mL$ is the initial volume of the gas

$p_2=3.50\cdot 10^{-2} torr$

1 torr is equivalent to 1 mmHg, so the conversion factor is the same as before, therefore the final pressure in atmospheres is:

$p_2 = 3.50\cdot 10^{-2} mmHg \cdot \frac{1}{760 mmHg/atm}=4.6\cdot 10^{-5} atm$

And so, the final volume of the krypton gas is:

$V_2=\frac{p_1 V_1}{p_2}=\frac{(0.400)(75.0)}{4.6\cdot 10^{-5}}=6.5\cdot 10^5 mL$

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4 years ago

A. Magnesium and Fluorine

natka813 [3]

Answer:

1)
a. MgF₂

b. NaF

c. Na₂O

d. AlI₃

a. MgS

b. MgF₂

c. HBr

d. Fe₂O₃

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3 years ago

Calculate the molarity of solution of "sodium sulfate" that contains 5.2 grams sodiums sulfate diluted to 500mL

wlad13 [49]

Taking into account the definition of molarity, the molarity of solution of sodium sulfate is 0.0732 $\frac{moles}{liter}$ .

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$Molarity=\frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$ .

<h3>Molarity of solution of sodium sulfate.</h3>

In this case, you have:

number of moles of sodium sulfate= $5.2 grams\frac{1 mole}{142 grams} = 0.0366 moles$ (being 142 g/mole the molar mass of sodiums sulfate)
volume= 500 mL= 0.5 L (being 1000 mL= 1 L)

Replacing in the definition of molarity:

$Molarity=\frac{0.0366 moles}{0.5 L}$

Solving:

Molarity= 0.0732 $\frac{moles}{liter}$

Finally, the molarity of solution of sodium sulfate is 0.0732 $\frac{moles}{liter}$ .

Learn more about molarity:

brainly.com/question/9324116

brainly.com/question/10608366

brainly.com/question/7429224

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2 years ago