Question

24

Answer 1

Answer:

Q = 52668 J

Explanation:

Given data:

Amount of heat required = ?

Mass of water = 350 g

Initial temperature = 20°C

Final temperature = 56°C

Specific heat capacity of water = 4.18 J/g°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 56°C - 20°C

ΔT = 36°C

Q = 350 g× 4.18 J/g°C ×36°C

Q = 52668 J