Question

If you have 0.50 L of 0.45 M sodium bromide. How many grams of sodium bromide are present?

Answer 1

Answer:

23.175g

Explanation:

0.45 mole of NaBr is in 1 liter

? moles of NaBr is in 0.50 liter

0.50 × 0.45 = 0.225 of NaBr

1 mole of NaBr = 23 + 80 = 103g

0.225 moles of NaBr = ?

0.225 × 103 = 23.175g