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kolbaska11 [484]
3 years ago
6

A) For the following reaction, K > 1. Classify each of the reactants and products based on their strength as Bronsted-Lowry a

cids or bases.
C9H7N + HNO2Doublearrow.GIFC9H7NH+ + NO2-

a) HNO2 1) stronger acid

b) NO2- 2) weaker acid

c) C9H7NH+ 3) stronger base

d) C9H7N 4) weaker base

B)
For the following reaction, K < 1. Classify each of the reactants and products based on their strength as Bronsted-Lowry acids or bases.

C5H11NH+ + C6H5COO-Doublearrow.GIFC5H11N + C6H5COOH

a) C5H11NH+ 1) strongest acid

b) C6H5COO- 2) stongest base

c) C5H11N 3) weakest acid

d) C6H5COOH 4) weakest base
Chemistry
1 answer:
Aleks04 [339]3 years ago
4 0

Answer:

Explanation:

According to Bronsted-Lowry acids or base theory ,  the reagent capable of giving hydrogen ion or proton  will be acid and that which accepts hydrogen ion or proton  will be base .

C₉H₇N + HNO₂   ⇄    C₉H₇NH⁺ + NO₂⁻

If K > 1 , reaction is proceeding from left to right .

Hence HNO₂ is giving H⁺ or proton and C₉H₇N is accepting proton to form

C₉H₇NH⁺ .  

Hence HNO₂ is bronsted acid and C₉H₇N is bronsted base .

B )

when K < 1 , reaction above proceeds from right to left . That means

C₉H₇NH⁺ is giving H⁺ so it is a bronsted acid and NO₂⁻ is accepting H⁺ so it is a bronsted base .

Hence ,  NO₂⁻ is a bronsted base and C₉H₇NH⁺ is a bronsted acid .

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when 2.4 g zinc is added to hydrochloric acid, 450 ml of hydrogen gas form at a temperature of 32 C what is the pressure of the
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First we need to find the number of moles of hydrogen gas formed
Zn + 2HCl ---> ZnCl₂ + H₂
stoichiometry of Zn to H₂ is 1:1
the number of Zn moles reacted - 2.4 g / 65.4 g/mol = 0.0367 mol
assuming Zn to be the limiting reactant 
number of Zn moles reacted = number of H₂ moles formed 
therefore number of H₂ moles formed = 0.0367 mol

we can use ideal gas law equation to find the pressure
PV = nRT
P - pressure
V - Volume - 450 x 10⁻⁶ m³
n - number of moles - 0.0367 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 32 °C + 273 = 305 K
substituting these values in the equation 
P x 450 x 10⁻⁶ m³ = 0.0367 mol x 8.314 Jmol⁻¹K⁻¹ x 305 K
P = 206.8 kPa 
pressure is 206.8 kPa
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Answer:

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Explanation:

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How many equivalents are in a solution that contains 0.25 moles Mg2+ and 0.50 moles Cl–?
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Answer:

Explanation:

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