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Anastaziya [24]
3 years ago
14

What is the value of the horizontal acceleration of a projectile?

Physics
1 answer:
Leni [432]3 years ago
7 0

Answer:

  a = F/m

Explanation:

Newton's first law tells you the horizontal acceleration will be the ratio of the net applied horizontal force to the mass of the projectile:

  a = F/m

The direction of the acceleration will be the direction of the applied force.

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Following a collision between a large spacecraft and an asteroid, a copper disk of radius 28.0 m and thickness 1.20 m, at a temp
coldgirl [10]

Answer:

A. 9.31 x10^10J

B. -8.47x10 ^ 12J

C. 8.38x 10^12J

Explanation:

See attached file pls

3 0
3 years ago
how much force would be required to produce 88 j of work when pushing a box 1.1meters at an angle of 10 degrees?
ycow [4]

Answer:81.235N

Explanation:

Work=88J

theta=10°

distance=1.1 meters

work=force x cos(theta) x distance

88=force x cos10 x 1.1 cos10=0.9848

88=force x 0.9848 x 1.1

88=force x 1.08328

Divide both sides by 1.08328

88/1.08328=(force x 1.08328)/1.08328

81.235=force

Force=81.235

5 0
3 years ago
The reckless risk taking found among many adolescents is most likely due to the effects of _______.
ivanzaharov [21]
The reckless risk taking found among many adolescents is most likely due to the effects of        <span>Peer pressure</span>
8 0
3 years ago
Read 2 more answers
The temperature of the cooling water as it leaves the hot engine of an automobile is 240 °F. After it passes through the radiato
djverab [1.8K]

Answer:571.09 kJ

Explanation:

Given

Temperature of cooling water from engine exit=240^{\circ} F\approx 115.55^{\circ}C

After Passing through the radiator its temperature decreases to 175^{\circ}F\approx 79.44^{\circ}F

specific heat of water=4.184 J/g^{\circ}C

Volume of water = 1 gallon\approx 3.78 L

density of water \rho =1 gm/mL

Thus mass of water=\rho \times V=3.78\times 1=3.78 kg

Heat transferred to the surrounding is equal to heat absorbed by cooling water

Q=m\cdot c\cdot \Delta T

Q=3.78\times 4.184\times 1000\times (115.55-79.44)

Q=3.78\times 4.184\times 1000\times (36.11)

Q=571.09 kJ

4 0
3 years ago
Please I need help! This is the last question I need for this assignment!
Ne4ueva [31]

Answer:

When the same amount of heat is added to cold sand and cold water, the temperature change of sand will be higher because of its lower specific heat capacity.

What is specific heat capacity?

Specific heat capacity is the quantity

of heat required to raise a unit mass of

a substance by 1 kelvin.

Specific heat capacity of water and sand

{<em>refer to the above attachment}</em>

Δθ = Q/mc

Thus, for an equal mass of water and sand, when the same amount of heat is added to cold sand and cold water, the temperature change of sand will be higher because of its lower specific heat capacity.

6 0
2 years ago
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