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Svetradugi [14.3K]
3 years ago
11

What are the two types of motion an object can experience when acted upon by balanced forces?

Physics
1 answer:
otez555 [7]3 years ago
6 0

Answer:

according to newton's first law of motion, when balanced forces are applied to an object:

  • an object at rest stays at rest
  • an object in motion continues its motion with a constant speed
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Read the scenario below and identify the Independent Variable, Dependent Variable, the Control group, and at least two Constants
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Explanation:

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What will happen to the fringe spacing if the wavelength of the light is decreased?.
REY [17]

Answer:

The formula is the form -

m λ = d sin Θ

As the wavelength λ is decreased sin Θ will also decrease.

One can see from the derivation that as the wavelength, being considered,

is decreased the dispersion will also decrease.

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3 years ago
Water is flowing in a pipe with a varying cross-sectional area, and at all points the water completely fills the pipe. At point
Salsk061 [2.6K]

Answer:

The fluids speed at a) 0.105\,m^{2}  and b) 0.047\,m^{2} are 2.33\,\frac{m}{s^{2}}  and 5.21\,\frac{m}{s^{2}} respectively

c) Th volume of water the pipe discharges is: 882\,m^{3}  

Explanation:

To solve a) and b) we should use flow continuity for ideal fluids:

\Delta Q=0(1)

With Q the flux of water, but Q is Av using this on (1) we have:

A_{2}v_{2}-A_{1}v_{1}=0 (2)

With A the cross sectional areas and v the velocities of the fluid.

a) Here, we use that point 2 has a cross-sectional area equal to A_{2}=0.105\,m^{2}, so now we can solve (2) for v_{2}:

v_{2}=\frac{A_{1}v_{1}}{A_{2}}=\frac{(0.070)(3.5)}{0.105}\approx2.33\,\frac{m}{s^{2}}

b) Here we use point 2 as A_{2}=0.047\,m^{2}:

v_{2}=\frac{A_{1}v_{1}}{A_{2}}=\frac{(0.070)(3.5)}{0.047}\approx5.21\,\frac{m}{s^{2}}

c) Here we need to know that in this case the flow is the volume of water that passes a cross-sectional area per unit time, this is Q=\frac{V}{t}, so we can write:

A_{1}v_{1}=\frac{V}{t}, solving for V:

V=A_{1}v_{1}t=(0.070m^{2})(3.5\frac{m}{s})(3600s)=882\,m^{3}

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4 years ago
Two planets X and Y travel counterclockwise in circular orbits about a star, as seen in the figure.
Vesnalui [34]

The angle of the planet is mathematically given as

dY= 704 degrees

<h3>What angle has planet Y rotated through during this time?</h3>

With Kepler's third rule, which states that a planet's orbit squared is a function of cubed radius, we can prove that this is the case.

Generally, the equation for the period is  mathematically given as

(periodX / periodY)^2 = (radius X / radius Y)^3

Therefore

(pX / pY)^2 = 4^3

(pX / pY)^2 = 64

\sqrt{(pX / pY )^2}= \sqrt{64}

(pX / pY=8

In conclusion, Because it takes 8 times longer to complete one orbit on planet X, planet Y travels 8 times farther than planet X does in the same time period...

planet Y travels ;

dY=8 * 88.0

dY= 704 degrees

Read more about Kepler's third rule

brainly.com/question/1086445

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2 years ago
Which parameter of the present universe, more than any other, is considered to be critical in determining the ultimate fate of t
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The slope and curvature of space time which is being derived from the Einstein's law of gravitation which was modified later it gives three slopes value (-,0,+ )
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