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Lemur [1.5K]
3 years ago
10

6. How many moles are in 25g of potassium?

Chemistry
1 answer:
Ahat [919]3 years ago
8 0
0.6394139898665671 that’s how many moles are in 25g of potassium !
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How many moles of H3PO4 would produce 12 moles of water in this reaction? ЗKOH + H3PO4 K3PO4 + 3H20
Olenka [21]

Answer:

4 moles of H₃PO₄

Explanation:

The reaction expression is given as;

     3KOH   + H₃PO₄   →   K₃PO₄   +  3H₂O

Number of moles of water  =  12moles

Unknown:

Number of moles of H₃PO₄ = ?

Solution:

 From the balanced reaction expression we see that;

          3 moles of water is produced from 1 mole of H₃PO₄

So;    12 moles of water would be produced from \frac{12}{3} = 4 moles of H₃PO₄

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3 years ago
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How many valence electrons does carbon have
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Carbon has 4 valence electrons, oxygen has 6
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how many kilograms of a 35% m/m sodium chlorate solution is needed to react completely with 0.29 l of a 22% m/v aluminum nitrate
Stolb23 [73]

Answer:- 0.273 kg

Solution:- A double replacement reaction takes place. The balanced equation is:

3NaClO_3+Al(NO_3)_3\rightarrow 3NaNO_3+Al(ClO_3)_3

We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.

0.29L(\frac{1000mL}{1L})(\frac{22g}{100mL})

= 63.8 g aluminum nitrate

From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.

We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.

63.8gAl(NO_3)_3(\frac{1mol}{212.99g})(\frac{3molNaClO_3}{1molAl(NO_3)_3})(\frac{106.44g}{1mol})

= 95.7gNaClO_3

sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate  and then the grams are converted to kg.

95.7gNaClO_3(\frac{100gSolution}{35gNaClO_3})(\frac{1kg}{1000g})

= 0.273 kg

So, 0.273 kg of 35% m/m sodium chlorate solution are required.

7 0
3 years ago
If a gas is moved from a large container to a small container but its temperature and number of moles remain the same, what woul
bazaltina [42]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

 

P1V1 =P2V2

<span>P2 = P1V1/V2</span>

<span>
</span>

<span>The correct answer is the first option. Pressure would increase. This can be seen from the equation above where V2 is indirectly proportional to P2.</span>

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What scientists do that is the basis for their investigation?
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Create a hypothesis, design an experiment the list varies really
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