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Alexeev081 [22]
2 years ago
7

Who made. Accurate atomic weight determination’s

Chemistry
1 answer:
lana66690 [7]2 years ago
6 0

Theodore Richards;  first scienstist to recieve nobel prize in Chemistry, earning the award "in recognition of his exact determinations of atomic weights of a large number of chemical elements."

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Type of reaction<br> PbSO. →<br> PbSO3 + __02<br> Type of reaction:
Marysya12 [62]

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1.

work out the mean mode median and range

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2 years ago
How many grams of N2 are in 44.8L at STP?
lutik1710 [3]

Answer: 10 i think

Explanation:

3 0
3 years ago
A sample of water is heated from 60.0 °C to 75.0°C by the addition of 140 j of
kupik [55]

Mass of the water : 2.23 g

<h3>Furter explanation</h3>

Heat

Q = m.c.Δt

m= mass, g

c = heat capacity, for water : 4.18 J/g° C.

ΔT = temperature

Q= 140 J

Δt = 75 - 60 = 15

mass of the water :

\tt m=\dfrac{Q}{c.\Delta T}=\dfrac{140}{4.18\times 15}=2.23~g

5 0
2 years ago
Classify each of the following reactants and products as an acid or base according to the Bronsted theory: H3PO4 + C6H5O- &lt;=&
Alexxandr [17]

Answer:

H₃PO₄ is an acid because donates the proton to fenolate.

Fenolate is the base because accepts the proton from the acid.

Explanation:

Bronsted theory mentioned that acid is the one that donates a proton to another compound and base is the one that receives it.

H₃PO₄   +   C₆H₅O⁻    ⇄      H₂PO₄⁻      +       C₆H₅OH

acid              base              conj. base            conj. acid

H₃PO₄ is an acid because donates the proton to fenolate.

Fenolate is the base because accepts the proton from the acid.

If we follow the dissociation, the diacid phosphate can donate two more protons, it is still a Bronsted acid, but it can act as an acid or a base. This is called amphoteric.

6 0
3 years ago
what mass of carbon dioxide gas would be produced if 10g of calcium carbonate reacted with an excess of hydrochloric acid?
LuckyWell [14K]
Answer is: 4,4 grams <span>of carbon dioxide gas would be produced.
</span>Chemical reaction: CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O.
m(CaCO₃) = 10 g.
n(CaCO₃) = 10 g ÷ 100 g/mol.
n(CaCO₃) = 0,1 mol.
From chemical reaction: n(CaCO₃) : n(CO₂) = 1 : 1.
n(CO₂) = 0,1 mol.
m(CO₂) = n(CO₂) · M(CO₂).
m(CO₂) = 0,1 mol· 44 g/mol.
m(CO₂) = 4,4 g.
7 0
3 years ago
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