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Alexeev081 [22]
3 years ago
7

Who made. Accurate atomic weight determination’s

Chemistry
1 answer:
lana66690 [7]3 years ago
6 0

Theodore Richards;  first scienstist to recieve nobel prize in Chemistry, earning the award "in recognition of his exact determinations of atomic weights of a large number of chemical elements."

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IrinaVladis [17]

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3 years ago
(I00p)A chemical equation example of a replacement of 1 ion for another in a compound! I need an example
snow_tiger [21]
A single replacement reaction could look like this:

2FeCl3 + 3Ba ➡️ 3BaCl2 + 2Fe

In this reaction, the barium is replacing the iron bound to the chlorine.
8 0
3 years ago
When 70.4 g of benzamide (C7H7NO) are dissolved in 850. g of a certain mystery liquid X, the freezing point of the solution is 2
Arlecino [84]

Answer:

1.62

Explanation:

From the given information:

number of moles of benzamide  =\dfrac{70.4 \ g}{121.14 \ g/mol}

= 0.58 mole

The molality = \dfrac{mass \ of \ solute (i.e. \ benzamide )}{mass \ of \ solvent  }

= \dfrac{0.58 }{0.85 }

= 0.6837

Using the formula:

\mathbf {dT  = l   \times  k_f  \times m}

where;

dT = freezing point = 27

l = Van't Hoff factor = 1

kf = freezing constant of the solvent

∴

2.7 °C = 1 × kf ×  0.6837 m

kf = 2.7 °C/ 0.6837m

kf = 3.949 °C/m

number of moles of NH4Cl = \dfrac{70.4 \ g}{53.491 \  g /mol}

= 1.316 mol

The molality = \dfrac{1.316 \ mol}{0.85 \ kg}

= 1.5484

Thus;

the above kf value is used in determining the  Van't Hoff factor for  NH4Cl

i.e.

9.9 = l × 3.949 × 1.5484 m

l = \dfrac{9.9}{3.949 \times 1.5484 \ m}

l = 1.62

5 0
3 years ago
What does I stand for?
tatuchka [14]
I: Current
V: Voltage
R: resistance
you’re welcome ;)
7 0
3 years ago
Read 2 more answers
How many carbon atoms are there in a 1.5-carat diamond? diamonds are a form of pure carbon. ( 1 carat=0.20 grams)?
11111nata11111 [884]
1 carot = 0.2 grams
1.5 carot = 0.3 grams.

1 mol of Carbon = 12 grams
x mol = 0.3 grams

0.3 * 1 = 12 x
x = 0.3/12
x = 0.025 mol

1 mol of Carbon is 6.02 * 10^23 atoms
0.025 mol of carbon is x

1/0.025 = 6.02*10^23 * /x
x = 0.025 * 6.02 * 10^23
x = 1.5 * 10^22 atoms of carbon.
5 0
3 years ago
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