Answer:
Step-by-step explanation:
Given:
A car starts with a dull tank of gas
1/7 of the gas has been used around the city.
With the rest of the gas in the car, the car can travel to and from Ottawa three times.
Question asked:
What fractions of a tank of gas does each complete trip to Ottawa use?
Solution:
Fuel used around the city = 
Remaining fuel after driving around the city = 1 -
= 
According to question:
As from the rest of the gas in the car that is 
, the car can complete 3 trip to Ottawa which means,
By unitary method:
The car can complete 3 trip by using = tank of gas.
The car can complete 1 trip by using = 
=
= 
= tank of gas
Thus, tank of gas used for each complete trip to Ottawa.
Answer:
3x^2 + 8
Step-by-step explanation:
Given functions,
f(x) = 3x + 8 ----(1)
g(x) = x^2 -----(2)
Since,
(fog)(x) = f( g(x) ) ( Composition of functions )
=f(x^2) ( From equation (2) )
=3x^2 + 8 ( From equation (1) )
Hence,
(fog)(x)=3x^2 + 8
Step-by-step explanation:
Answer:
ferris wheel travel approx = 434.72 ft
Step-by-step explanation:
given data
wheel rotates = 9pi/8 radians
total height of the ferris wheel = 246 ft
solution
we can say here that height of the ferris wheel is same as the diameter of the wheel
and wheel is circular in shape
so we get here first radius of wheel that is
radius = half of diameter ..........................1
put here value and we get
radius = 0.5 × 246
radius = 123 ft
and
wheel travel distance = length of arc by a angle of wheel rotates
so here length of arc will be
arc length = radius × wheel rotates angle .....................2
put here value and we get
arc length = 123 × 
arc length = 434.7178 ft
so ferris wheel travel approx = 434.72 ft
4/7, because both the numerator and denominator can be divisible by 3.
