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nikitadnepr [17]
3 years ago
15

Find the sum. ∠1 + ∠2 + ∠3 + ∠4 =

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
8 0

It will be 360°.

________________

gizmo_the_mogwai [7]3 years ago
6 0

Answer:

360°

Step-by-step explanation:

It would be the same thing as finding the sum of a rectangle where all 4 angles add up to 360° or think of it as a circle where circles = to 360° (I hope this makes sense)

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Which of the following illustrates the truth value of the given conditional statement? If dogs have five legs, then cats have th
jeka94
Answer: In this conditional statement, all of the results are F.

There is no relationship between dogs having five legs and cats having three tails. Even if you took the converse and said "If cats have three tails, then dogs have five legs", there is no truth in that statement.
4 0
3 years ago
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I need some help with this calculus 1 implicit diffrention problem?
katen-ka-za [31]

Answer:

y" = -24 / y³

Step-by-step explanation:

6x² + y² = 4

Take the derivative of both sides with respect to x.

12x + 2y y' = 0

Again, take the derivative of both sides with respect to x.

12 + 2y y" + y' (2y') = 0

12 + 2y y" + 2(y')² = 0

Solve for y' in the first equation.

2y y' = -12x

y' = -6x/y

Substitute and solve for y":

12 + 2y y" + 2(-6x/y)² = 0

12 + 2y y" + 2(36x²/y²) = 0

12 + 2y y" + 72x²/y² = 0

6y² + y³ y" + 36x² = 0

y³ y" = -36x² − 6y²

y" = (-36x² − 6y²) / y³

Solve for y² in the original equation and substitute:

y² = 4 − 6x²

y" = (-36x² − 6(4 − 6x²)) / y³

y" = (-36x² − 24 + 36x²) / y³

y" = -24 / y³

7 0
3 years ago
How many grams are there in 4.5 kilograms
zavuch27 [327]

Answer: 4500 grams

Step-by-step explanation: 1 kilogram is 1,000 grams, so 4 kilograms is 4,000 grams, and half a kilogram is 500 grams. So, 4000 + 500 = 4,500

3 0
3 years ago
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ANSWER ASAP PLEASE!!!
Thepotemich [5.8K]

area of triangle = 1/2(3)(4) = 6 in^2

area of rectangle = 3 x 10 = 30 in^2

area of trapezoid = 1/2(3+5)(2) = 8 in^2


area of the figure: 6 in^2 + 30 in^2 + 8 in^2 = 44 in^2


answer

44 in^2

3 0
3 years ago
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If f (n)(0) = (n + 1)! for n = 0, 1, 2, , find the taylor series at a=0 for f.
Pie
Given that f^{(n)}(0)=(n+1)!, we have for f(x) the Taylor series expansion about 0 as

f(x)=\displaystyle\sum_{n=0}^\infty\frac{(n+1)!}{n!}x^n=\sum_{n=0}^\infty(n+1)x^n

Replace n+1 with n, so that the series is equivalent to

f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}

and notice that

\displaystyle\frac{\mathrm d}{\mathrm dx}\sum_{n=0}^\infty x^n=\sum_{n=1}^\infty nx^{n-1}

Recall that for |x|, we have

\displaystyle\sum_{n=0}^\infty x^n=\frac1{1-x}

which means

f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}=\frac{\mathrm d}{\mathrm dx}\frac1{1-x}
\implies f(x)=\dfrac1{(1-x)^2}
5 0
3 years ago
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