Question

A spring is hung from the ceiling. A 0.442-kg block is then attached to the free end of the spring. When released from rest, the block drops 0.150 m before momentarily coming to rest, after which it moves back upward. (a) What is the spring constant of the spring

Answer 1

Answer:

$K=58.8N/m$

Explanation:

From the question we are told that:

Mass $M=0.442$

Drop distance $d=0.150$

Generally the equation for Spring Constant is mathematically given by

 $K=\frac{2mg}{x}$

 $K=\frac{2*0.442*9.8}{1.150}$

 $K=58.8N/m$