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3 years ago

6

El Nino begins with which of the following?

2 answers:

Rudik [331]3 years ago

6 0

The eastward movement of winds and currents in the pacific

Nana76 [90]3 years ago

6 0

Answer: the eastward movement of winds and currents in the pacific.

El Nino is an abnormal weather condition which occurs due to the warming of the Pacific ocean near the equator. This occurs due to the fact that the sun warms the water near the equator, this results in formation of massive amount of clouds and rain. The westward- blowing trade winds moves towards the equator. This results in change in the air pressure and wind speed causing warm surface water to move eastwards along the Equator and the currents in the Pacific moves towards the coast of northern South America.

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Is the arctic ocean larger than the indian ocean?

Alik [6]

The Arctic Ocean is the smallest ocean. It is more than five times smaller than Indian and Atlantic Oceans.

5 0

3 years ago

What is the acceleration due to gravity?<br> А<br> B<br> 9.2<br> 12.3<br> С<br> 8.83<br> D<br> 9.81

SCORPION-xisa [38]

Correct answer:

D) 9.81

8 0

3 years ago

An atom of carbon has a radius of 67.0 pm and the average orbital speed of the electrons in it is about 1.3 x 10⁶ m/s.

adoni [48]

Answer :

The least possible uncertainty in an electron's velocity is, $4.32\times 10^{5}m/s$

The percentage of the average speed is, 33 %

Explanation :

According to the Heisenberg's uncertainty principle,

$\Delta x\times \Delta p=\frac{h}{4\pi}$ ...........(1)

where,

$\Delta x$ = uncertainty in position

$\Delta p$ = uncertainty in momentum

h = Planck's constant

And as we know that the momentum is the product of mass and velocity of an object.

$p=m\times v$

or,

$\Delta p=m\times \Delta v$ .......(2)

Equating 1 and 2, we get:

$\Delta x\times m\times \Delta v=\frac{h}{4\pi}$

$\Delta v=\frac{h}{4\pi \Delta x\times m}$

Given:

m = mass of electron = $9.11\times 10^{-31}kg$

h = Planck's constant = $6.626\times 10^{-34}Js$

radius of atom = $67.0pm=67.0\times 10^{-12}m$ $(1pm=10^{-12}m)$

$\Delta x$ = diameter of atom = $2\times 67.0\times 10^{-12}m=134.0\times 10^{-12}m$

Now put all the given values in the above formula, we get:

$\Delta v=\frac{6.626\times 10^{-34}Js}{4\times 3.14\times (134.0\times 10^{-12}m)\times (9.11\times 10^{-31}kg)}$

$\Delta v=4.32\times 10^{5}m/s$

The minimum uncertainty in an electron's velocity is, $4.32\times 10^{5}m/s$

Now we have to calculate the percentage of the average speed.

Percentage of average speed = $\frac{\text{Uncertainty in speed}}{\text{Average speed}}\times 100$

Uncertainty in speed = $4.32\times 10^{5}m/s$

Average speed = $1.3\times 10^{6}m/s$

Percentage of average speed = $\frac{4.32\times 10^{5}m/s}{1.3\times 10^{6}m/s}\times 100$

Percentage of average speed = 33.2 % ≈ 33 %

Thus, the percentage of the average speed is, 33 %

3 0

3 years ago

Which of the following planets were the ancient Greeks able to see and make careful observations of?

zepelin [54]

Answer:

Neptune and Uranus

Explanation:

Did a quiz on this not to long ago

5 0

2 years ago

A bus starts from rest and accelerates to 14 m/s in 4 s. What is the

Komok [63]

Acceleration = 14/4 = ....

3 0

3 years ago