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4 years ago

Which equation is most likely used to determine the acceleration from a velocity vs:time graph?

2 answers:

7 0

Acceleration, a = (v - u)/t

where v is the final velocity, u is the initial velocity, and t is the time.

This formula on a velocity time graph represents the slope of the graph.

Mars2501 [29]4 years ago

3 0

Answer: Hello there!

in this case, you have a graph of velocity vs time, then in this graph is represented the function v(t).

The acceleration is defined as the integral with respect to the time of the velocity v(t), then we could calculate the mean acceleration between two times in a next way:

$a = \frac{v(t2) - v(t1))}{t2 -t1}$

this is the slope between the times t2 and t1, where t2>t1 and V(t2) is the velocity at the time t2 (the final velocity) and v(t1) is the velocity at the time t1 (the initial velocity). In this case, a is the mean acceleration between these times.

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A solenoidal coil with 25 turns of wire is wound tightly aroundanother coil with 300 turns. The inner solenoid is 25.0 cm long a

Aneli [31]

Answer:

(a). The average magnetic flux through each turn of the inner solenoid is $5.68\times10^{-8}\ Wb$

(b). The mutual inductance of the two solenoids is $1.183\times10^{-5}\ H$

(c). The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.0207 V.

Explanation:

Given that,

Number of turns of coil = 25

Number of turns of another coil = 300

Length = 25.0 cm

Diameter = 2.00 cm

Current = 0.120 A

Rate $\dfrac{di_{2}}{dt}=1.75\times10^{3}\ A/s$

(a). We need to calculate the magnetic field due to inner solenoid

Using formula of magnetic field

$B=\mu_{0}(\dfrac{N_{2}}{l})I$

Put the value into the formula

$B=4\pi\times10^{-7}\times(\dfrac{300}{0.25})\times0.120$

$B=1.81\times10^{-4}\ T$

We need to calculate the average magnetic flux through each turn of the inner solenoid

Using formula of magnetic flux

$\phi=B\cdot A$

Put the value into the formula

$\phi=1.81\times10^{-4}\times\pi\times (1.00\times10^{-2})^2$

$\phi=5.68\times10^{-8}\ Wb$

The average magnetic flux through each turn of the inner solenoid is $5.68\times10^{-8}\ Wb$

(b). We need to calculate the mutual inductance of the two solenoids

Using formula of mutual inductance

$M=\dfrac{N_{1}\phi}{i_{1}}$

Put the value into the formula

$M=\dfrac{25\times5.68\times10^{-8}}{0.120}$

$M=0.00001183\ H$

$M=1.183\times10^{-5}\ H$

The mutual inductance of the two solenoids is $1.183\times10^{-5}\ H$

(c). We need to calculate the emf induced in the outer solenoid by the changing current in the inner solenoid

Using formula of emf

$\epsilon=-M\dfrac{di_{2}}{dt}$

Put the value into the formula

$\epsilon=-1.183\times10^{-5}\times1.75\times10^{3}$

$\epsilon=-0.0207\ V$

The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.0207 V.

Hence, (a). The average magnetic flux through each turn of the inner solenoid is $5.68\times10^{-8}\ Wb$

(b). The mutual inductance of the two solenoids is $1.183\times10^{-5}\ H$

(c). The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.0207 V.

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3 years ago

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3 years ago

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Rudik [331]

Answer:

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3 years ago

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Hi, why do waves with longer wavelengths travel further than waves with shorter wavelengths?

oee [108]

Answer:

ones longer than the other daa

Explanation:

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3 years ago

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An object on a spring oscillates in simple harmonic motion with frequency f = 1 Hz. If the spring is exchanged for a new one wit

tankabanditka [31]

Answer:

Explanation:

Given

Frequency of an object in SHM is $f=1\ Hz$

Frequency in SHM is given by

$f=\frac{1}{2\pi }\sqrt{\frac{k}{m}}$

where k=spring constant

m=mass of object

if spring is exchanged such that new spring constant is half of previous one then

$k'=0.5 k$

$f'=\frac{1}{2\pi }\sqrt{\frac{0.5 k}{m}}$

$f'=\frac{1}{\sqrt{2}}\times \frac{1}{2\pi }\sqrt{\frac{k}{m}}$

i.e. $f'=\frac{1}{\sqrt{2}}\times 1$

$f'=\frac{1}{\sqrt{2}}$

$f'=0.707\ Hz$

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4 years ago