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lbvjy [14]
3 years ago
10

What would its weight be on Jupiter? 24.9N

Physics
2 answers:
navik [9.2K]3 years ago
7 0
The weight would be 62.92.
Stells [14]3 years ago
5 0

Answer:

1.898 × 10^27 kg

Explanation:

thats how much it ways

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rjkz [21]

Answer:

Star S has radial motion

Explanation:

Because the radial motion stracture is kinda similar to hydrogen spectrum(I'm guessing,only lol)

3 0
2 years ago
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Please help on this one? PLEASE.
Fantom [35]

Answer: The answer is D

Explanation:

6 0
3 years ago
A 2-lb slider is propelled upward at A along the fixed curved bar which lies in a vertical plane. If the slider is observed to h
timofeeve [1]

To develop this problem it is necessary to apply the concepts given in the balance of forces for the tangential force and the centripetal force. An easy way to detail this problem is through a free body diagram that describes the behavior of the body and the forces to which it is subject.

PART A) Normal Force.

F_n = \frac{mv^2}{r}

N+mgcos\theta = \frac{mv^2}{r}

Here,

Normal reaction of the ring is N and velocity of the ring is v

N+mgcos\theta = \frac{mv^2}{r}

N+Wcos\theta = \frac{W}{g} (\frac{v^2}{r})

N+2cos30\° = \frac{2}{32.2}*\frac{10^2}{2}

N = 1.374lb

PART B) Acceleration

F_t = ma_t

-mgsin\theta = ma_t

-W sin\theta = \frac{W}{g} a_t

-2Sin30\° = (\frac{2}{32.2})a_t

a_T = -16.10ft/s^2

Negative symbol indicates deceleration.

<em>NOTE: For the problem, the graph in which the turning radius and the angle of suspension was specified was not supplied. A graphic that matches the description given by the problem is attached.</em>

8 0
3 years ago
The thermal energy used by heater in 3 minutes is used to melt wax.Melting point of solid wax is 60.Specific heat of wax is 220j
Romashka-Z-Leto [24]

Answer:

m = 35 g

Explanation:

The specific heat of a material can be calculated by the following formula:

C = \frac{Q}{m}\\

where,

C = Specific Heat of Wax = 220 J/g

Q = Amount of Heat Supplied by the Heater = 7700 J

m = mass of wax melted = ?

Therefore,

220\ J/g = \frac{7700\ J}{m}\\\\m = \frac{7700\ J}{220\ J/g}\\

<u>m = 35 g </u>

5 0
2 years ago
Why do most amphibians return to the water to reproduce?
Ymorist [56]
C. amphibian eggs do not contain a protective shell
5 0
1 year ago
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