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3 years ago

Storage of unlimited quantities of energy in batteries is possible. TrueFalse

Physics

2 answers:

Damm [24]3 years ago

4 0

the answer is false theres no such thing as unlimited energy, energy is always gained from sth

dangina [55]3 years ago

3 0

False

It is impossible to get infinite energy let alone to put it inside one battery

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A 40 kg-skier starts at the top of a 12-meter high slope. At the bottom, she is traveling 10 m/s. How much energy does she lose

julia-pushkina [17]

2704 j is my answer i did the math. good luck

8 0

3 years ago

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In 1656, the Burgmeister (mayor) of the town of Magdeburg, Germany, Otto Von Guericke, carried out a dramatic demonstration of t

tino4ka555 [31]

The force required to pull the two hemispheres is 46622.72N

<h3>Calculation and Parameters</h3>

( Note: 1 millibar=100 N/m2. One atmosphere is 1013 millibar = 1.013×105 N/m2 ]

The contact area between the hemispheres is (pi x 0.400^2) = 0.5024m^2.

Pressure difference = (940 - 12)

= 928 millibars.

(928 x 100)

= 92,800N/m^2.

Therefore, the required force to pull the two hemispheres is

(92800 x 0.5024)

= 46622.72N.

Read more about force here:

brainly.com/question/15300777

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1 year ago

An object is dropped from a height H. During the final second of its fall, it traverses a distance of 53.2 m. What was H? An obj

Serhud [2]

Answer:

H = 171.90 m

Explanation:

given data

distance = 53.2 m

height = H

to find out

height H

solution

we know height is here H = $\frac{1}{2} gt^2$ ......................1

here t is time and a is acceleration

we find t first

we know during time (t -1) s , it fall distance (H - 53.2) m

so equation of distance

$H - 53.2 = \frac{1}{2} g (t-1)^2$

$H - 53.2 = \frac{1}{2} g (t^2-2t+1)$

$H - 53.2 = \frac{1}{2} gt^2-gt+\frac{1}{2} g$ ................2

now subtract equation 2 from equation 1 so we get

$H - (H - 53.2) =\frac{1}{2} gt^2- (\frac{1}{2} gt^2-gt+\frac{1}{2} g)$

53.2 = gt - $\frac{1}{2} g$

53.2 = 9.81 t - $\frac{1}{2} 9.8$

t = 5.92 s

so from equation 1

H = $\frac{1}{2} (9.81)5.92^2$

H = 171.90 m

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2 years ago

An object moving with a constant

jeka57 [31]

Answer:

Acceleration:

${ \tt{a = \frac{v - u}{t} }} \\ { \tt{a = \frac{20 - 10}{5} }} \\ { \tt{a = 2 \: m {s}^{ - 2} }}$

From third equation:

${ \bf{ {v}^{2} = {u}^{2} + 2as}} \\ { \tt{s = \frac{ {20}^{2} - {10}^{2} }{2 \times 2} }} \\ = { \tt{s = 75 \: m}}$

5 0

2 years ago

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Concave lens cause rays to _____.

Molodets [167]

Diverge or spread apart.

5 0

3 years ago