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3 years ago

The express train can travel 100 miles per hour. This information describes the train's

Physics

2 answers:

Tomtit [17]3 years ago

7 0

Speed. This ONLY includes the miles per hour. If it had a direction it would be velocity.

valentina_108 [34]3 years ago

7 0

Speed Is The Correct Answer

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After driving a portion of the route, the taptap is fully loaded with a total of 27 people including the driver, with an average

belka [17]

We will define the Total mass to calculate the force, so our values are: $M_p = 69*27=1823Kg\\M_g=15*3=45Kg\\M_c=3*5=15Kg\\M_B=25Kg$

Total Mass $= 1863+45+15+25=1948Kg$

The Weight is,

$F=mg=1948*98=19090.4N$

Through the hook's Law we calculate X.

$F_s=Kx$ , where x is the lenght of compression and K the Spring constant.

We don't have a K-Spring, but we can assume a random value (or simply let the equation in function of K)

$X = \frac{F_s}{x} \\X = \frac{1909.4}{k}$

I assume a value of $K=4*10^4N/m$

$X= \frac{1909.4}{4*10^4} = 0.48m$

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3 years ago

Ayan warms some hot chocolate in a microwave oven. Which reasoning explains how the particles that make up the hot chocolate dif

valkas [14]

Answer:

They move farther apart

Explanation:

When objects heat up they expand for example heating up a balloon makes it expand

4 0

3 years ago

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Two boys are sliding toward each other on a frictionless, ice-covered parking lot. Jacob, mass 45 kg, is gliding to the right at

Maurinko [17]

Answer:

$v=0.3381\ m.s^{-1}$ in the direction of motion of Jacob

Explanation:

Given:

mass of Jacob, $m_j=45\ kg$

velocity of Jacob, $v_j=8.08\ m.s^{-1}$

mass of Ethan, $m_e=31\ kg$

velocity of Ethan, $v_e=10.9\ m.s^{-1}$

Now using the conservation of linear momentum for the case:

(When the two masses in motion combine to form one after the collision then they will move together in the direction of the greater momentum.)

$(m_j+m_e).v=m_j.v_j-m_e.v_e$

$(45+31)\times v=45\times 8.08-31\times 10.9$

$v=0.3381\ m.s^{-1}$ in the direction of motion of Jacob as it was assumed to be positive.

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3 years ago

How far will it go, given that the coefficient of kinetic friction is 0.10 and the push imparts an initial speed of 3.9 m/s ?

Akimi4 [234]

Answer:19.5 m

Explanation:

Given

coefficient of kinetic Friction $\mu _k=0.10$

Initial speed $u=3.9\ m/s$

Friction is present so it tries to stop to the object and stops it completely after moving certain distance let say s

maximum deceleration provided by friction is

$a_{max}=\mu _k\cdot g$

$a_{max}=0.1\times 3.9=0.39\ m/s^2$

using equation of motion

$v^2-u^2=2 as$

where $v=final\ velocity$

$u=initial velocity$

$a=acceleration$

$s=displacement$

$(0)-(3.9)^2=2\times (-0.39)\times s$

$s=19.5\ m$

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3 years ago

A spring of mass

Dominik [7]

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3 years ago

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