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muminat
3 years ago
14

Choose

Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:

Option D

N • m2/C2

Explanation:

The Cuolomb force constant also known as electric force constant, 1/4πε0

is given as a product of force acting in a unit area per square cuolomb hence its unit is Newton squared metre per square cuolomb as represented by N • m2/C2

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James has a mass of 98 kg and Basma has a mass of 59 kg. James is running at 3.0 m/s, while Basma is running at 4.0 m/s.
masha68 [24]

(a) James has the most momentum which is 294 kgm/s.

(b) The resultant force acting on Basma is 90.78 N.

(c) The time taken for James to stop is 3.2 seconds.

<h3>Momentum of each person</h3>

Momentum of James: P = mv = 98 x 3 = 294 kgm/s

Momentum of Basma: P = mv = 59 x 4 = 236 kgm/s

<h3>Resultant force of Basma</h3>

F = ma = mv/t = P/t = 236/2.6 = 90.78 N

<h3>Time for James to stop</h3>

F = P/t

t = P/F

t = 294/90.78

t = 3.2 s

Learn more about momentum here: brainly.com/question/7538238

#SPJ1

4 0
2 years ago
The kinetic and potential energies of an object both always depend on which property?.
hichkok12 [17]

Answer:

the object's position.

Explanation: might help ion know

5 0
3 years ago
Which of the following is an example of rotation
SOVA2 [1]
I believe it is D. Earth spinning on it's axis.
8 0
3 years ago
A parallel-plate capacitor in air has a plate separation of 1.31 cm and a plate area of 25.0 cm2. The plates are charged to a po
morpeh [17]

Answer:

a) before immersion

C = εA/d = (8.85e-12)(25e-4)/(1.31e-2) = 1.68e-12 F

q = CV = (1.68e-12)(255) = 4.28e-10 C

b) after immersion

q = 4.28e-10 C

Because the capacitor was disconnected before it was immersed, the charge remains the same.

c)*at 20° C

C = κεA/d = (80.4*)(8.85e-12)(25e-4)/(1.31e-2) = 5.62e-10 F

V = q/C = 4.28e-10 C/5.62e-10 C = 0.76 V

e)

U(i) = (1/2)CV^2 = (1/2)(1.68e-12)(255)^2 = 5.46e-8 J

U(f) = (1/2)(5.62e-10)(0.76)^2 = 1.62e-10 J

ΔU = 1.62e-10 J - 5.46e-8 J = -3.84e-8 J

8 0
3 years ago
What force must the worker exert to get the box moving &amp; what force must the worker exert to accelerate the box at 0.1 meter
photoshop1234 [79]

Since static friction is the minimum force required to just start the motion of a stationary object.

Here if we need to start an object from rest then we required F = 700 N

So for the first part of the above problem Force will be F = 700 N

Now if the box is already moving then we will have to use kinetic friction force between box and floor

now we can write the equation of net force as

F - F_k = m*a

here

F_k = kinetic friction = 220 N

m = mass = 500 kg

a = acceleration = 0.1 m/s^2

now we will have

F - 220 = 500* 0.1

F = 220 + 50 = 270 N

3 0
3 years ago
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