How dose the speed of the sound differ in water, iron, and Helium?
1 answer:
Answer:
air water iron helium
v(m/s) 280 2200 17780 39682
Explanation:
The speed of a wave depends on the physical properties of the medium where it travels, in the case of a longitudinal wave such as sound, it depends on the resistance to deformation (volume modulus and the density of the medium
v =
in the mentioned materials they are constant
air water iron helium
B 1 10⁵ 2.2 10⁹ 140 10⁹ 0.05 10⁹
ρ 1.28 997 7874 1.26
v(m/s) 280 2200 17780 39682
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Answer:
<em>a) 105935.7 Pa</em>
<em>b) 103630.35 Pa</em>
Explanation:
The volume of the container = 0.025 m^3
The radius of the container = 13 cm = 0.13 m
We have to find the height of the tank
From the equation for finding the volume of the cylinder,
V =
where
V is the volume of the cylinder
h is the height of the cylinder
substituting values, we have
0.025 = 3.142 x x h
0.025 = 0.0531h
h = 0.025/0.0531 = 0.47 m
Pressure at the bottom of the tank P = ρgh
where
ρ is the density of water = 1000 kg/m^3
g is the acceleration due to gravity = 9.81 m/s^2
h is the depth of water which is equal to the height of the tank
substituting values, we have
P = 1000 x 9.81 x 0.47 = 4610.7 Pa
atmospheric pressure = 101325 Pa
therefore, the pressure in the tank bottom above atmospheric pressure = 101325 Pa + 4610.7 Pa = <em>105935.7 Pa</em>
b) For half way down the container, depth of water will be = 0.47/2 = 0.235 m
pressure P = 1000 x 9.81 x 0.235 = 2305.35 Pa
This pressure above atmospheric pressure = 101325 Pa + 2305.35 Pa = <em>103630.35 Pa</em>