Answer:
0.114 kg or 114 g
Explanation:
From the diagram attaches,
Taking the moment about the fulcrum,
sum of clockwise moment = sum of anticlockwise moment.
Wd = W'd'
Where W = weight of the mass, W' = weight of the meter rule, d = distance of the mass from the fulcrum, d' = distance of the meter rule.
make W' the subject of the equation
W' = Wd/d'................ Equation 1
Given: W = mg = 0.0515(9.8) = 0.5047 N, d = (39.2-16) = 23.2 cm, d' = (49.7-39.2) = 10.5 cm
Substitute these values into equation 1
W' = 0.5047(23.2)/10.5
W' = 1.115 N.
But,
m' = W'/g
m' = 1.115/9.8
m' = 0.114 kg
m' = 114 g
3.5 Newton of force is needed to accelerate 140g of ball at 25 m/s^2 using the formula f=ma
Change 140g to kg
(a) Frequency of sound wave is inversely proportional to string length.
(b) Pitch of a sound depends on the frequency while loudness depends on the amplitude of sound.
<h3>
Relationship between string length and frequency</h3>
The relationship between string length and frequency is given as;
λ = 2L
where;
- λ is wavelength
- L is length of the string
v = fλ
f = v/λ
f = v/2L
Thus, frequency of sound wave is inversely proportional to string length.
<h3>Relationship between pitch and loudness of sound</h3>
The pitch of a sound depends on the frequency while loudness of a sound depends on the amplitude of sound waves.
Learn more about pitch and loudness here: brainly.com/question/61859
Answer:
a. 25000 J
b. 2500 J/s
Explanation:
Given,
Distance ( s ) = 50 m
Force ( f ) = 500 N
a.
To find : -
Work done ( W ) = ?
Formula : -
W = fs
W
= 500 x 50
= 25000 J
Therefore,
the work done by the force the horse exerts is
25000 J.
b.
To find : -
Power ( P ) = ?
Formula : -
W = Pt
P = W / t
P
= 25000 / 10
= 2500 J/s
Therefore,
the power produced if the movement took 10 s
is 2500 J/s.
Answer is D.
Speed:
Use relative speed to simplify the situation. Since the trains are moving in opposite directions, you can add the speeds and pretend the first train is stationary (moving at 0m/s) and the second train is moving at 50m/s.
Distance:
The front of the second train needs to travel 120m to get from the front to the back of the first train. When the front of the second train is at the back of the first train, the back of the second train is still 10m in front of the first train. The back therefore has to travel 130m to clear the first train. The total distance over which the trains are overlapping in this scenario is therefore 120 + 130 = 250m.
You have speed and you have distance so now just calculate time:
v = d / t
50 = 250 / t
t = 5s
