Answer:
1.045 m from 120 kg
Explanation:
m1 = 120 kg
m2 = 420 kg
m = 51 kg
d = 3 m
Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.
By use of the gravitational force
Force on m due to m1 is equal to the force on m due to m2.



3 - y = 1.87 y
3 = 2.87 y
y = 1.045 m
Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.
Answer:
Explanation:
Energy E is conserved:

If v₀ = 22m/s, h₀=0m and h₁=25m:

Solving for v₁:

There is no real solution, because the stone never reaches 25m.
Answer:
Possible options:
A. nA, nC, nB
B. nA, nB, nC
C. nC, nB, nA
D. nC, nA, nB
E. nB, nA, nC
Answer is D
Explanation:
When the light is refracted into liquid B it is bent away from the normal, so that nA > nB. When the light is refracted into liquid C it is bent toward the normal, so that nC > nA. Therefore, we conclude that nC > nA > nB
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