Assuming you mean f(t) = g(t) × h(t), notice that
f(t) = g(t) × h(t) = cos(t) sin(t) = 1/2 sin(2t)
Then the difference quotient of f is
Recall the angle sum identity for sine:
sin(x + y) = sin(x) cos(y) + cos(x) sin(y)
Then we can write the difference quotient as
or
(As a bonus, notice that as h approaches 0, we have (cos(2h) - 1)/(2h) → 0 and sin(2h)/(2h) → 1, so we recover the derivative of f(t) as cos(2t).)
The answer would be 6. Why? It's because of the 24%. You have to change the 24 into 0.24. If you left it alone, the process would be confusing. Changing it into a decimal is much easier. After you changed the percent into a decimal, multiply the 25. You should get 6 as an answer.
The equations used to find the measure of each angle in degrees is x + y = 90 and x = 6y - 1
The two complementary angles are 77 degrees and 13 degrees
<em><u>Solution:</u></em>
Given that two angles are complementary angles
Complementary angles are two angles whose sum is 90 degrees
Let one of the angle be "x" and the other angle be "y"
Therefore,
x + y = 90 ------ eqn 1
Also given that,
One angle is one less than six times the measure of another
one angle = six times the other angle - 1
x = 6y - 1 ------ eqn 2
Substitute eqn 2 in eqn 1
6y - 1 + y = 90
Thus the above equation is used to find the measure of each angle in degrees
Solve the above equation
6y + y - 1 = 90
7y - 1 = 90
7y = 91
y = 13
Substitute y = 13 in eqn 2
x = 6(13) - 1
x = 78 - 1
x = 77
Thus the two complementary angles are 77 degrees and 13 degrees
Answer:
<h3>55 secs</h3>
Step-by-step explanation:
Given the elevation h (in feet) of the balloon modeled by the function h(x)=−6x+330, we can calculate the time it takes the balloon to reach the ground. The hot air balloon hits the ground at h(x) = 0.
Substitute h(x) = 0 into the modeled expression and find x as shown;
h(x)=−6x+330
0 = −6x+330
6x = 330
Divide both sides by 6
6x/6 = 330/6
x = 55 seconds
Hence the hot air balloon hits the ground after 55 seconds
X²/9 + y²/16 = 1
The general for mula of an ellipse is:
(x-h)²/a² + (y-k)²/b² = 1. Since h = k = 0, this ellipse
x²/9 + y²/16 = 1
passes by the center O. (Note that a = 3 and b = 4)
Moreover sin b>a so the majore axis is (on the y-axis) and a the minor axis (on the x-axis) [Its shape is as a vertical egg].
On a system of perpendicular axis that intercept in O., take on the x-axis 2 points A & B with respective coordinate A(3.0) and B(-3,0)
On the y-axis your report A'(0,+4) and B'(0,-4). So you have the vertex of the ellipse, then it's easy to draw it
