3 years ago

Can somebody please help me?

Mathematics

1 answer:

klasskru [66]3 years ago

8 0

Answer:

TRUE!!!!!!!!!!!!!!!!!! BRANLIST

Step-by-step explanation:

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3 years ago

Can somebody help me with (a) and (b)? Thanks! :D

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3 years ago

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3 years ago

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Vilka [71]

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3 years ago

Please find the answer to this function! F(2)= 6x^4-10x^3+40x-50

steposvetlana [31]

<u>Answer-</u>

$f(2)= 6x^4-10x^3+40x-50=46$

<u>Solution-</u>

The given function is,

$\Rightarrow f(x)= 6x^4-10x^3+40x-50$

Now, we have to find the value of f(x) at x=2 i.e f(2), so putting x as 2 in the given function,

$\Rightarrow f(2)= 6(2)^4-10(2)^3+40(2)-50$

$\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50$

$\Rightarrow f(2)= 96-80+80-50$

$\Rightarrow f(2)= 96-50$

$\Rightarrow f(2)= 46$

Therefore, f(2) was found to be 46.

7 0

4 years ago