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Digiron [165]
3 years ago
12

What it meant by executive mention the function of Executive​

Chemistry
1 answer:
Natalija [7]3 years ago
7 0

\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:⌐■-■}}}}}

Definition:-

The organ of government that primarily looks after the function of implementation and administration is called the executive.

Function:-

Executive is the branch of government responsible for the implementation of laws and policies adopted by the legislature.

  • Thanks
  • Hope it helps.

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A chemist titrates 150.0 mL of a 0.2653 M carbonic acid (H2CO3) solution with 0.2196 M NaOH solution at 25 °C. Calculate the pH
xxTIMURxx [149]

Answer:

9.3

Explanation:

This is long and complicated so get ready

We are going to use the conjugate base of carbonic acid with water to make carbonic acid and OH- (Na is simply a spectator ion and is irrelavent here)

Let the conjugate base be A- and Carbonic acid be HA

A- + H20 ⇄ HA + OH-

To find the concentration of A- we must find the concentration of the reactants given. We know this will be equal because it is a strong base and all of it disassociates.

to get moles of acid we take the concentration and multiply by liters to cancel

.2653 x .150 = .039795 mol HA

Because it is at equivalence point we know the moles will be equal. We are given the concentration so we only have to solve for liters

We plug it into the equation and found: .181 L

Now use moles and combined volums to fins concentrarion which is .120 M

Now plug that use the Ka converted to Kb to find the cincentrations of HA and OH-

Ka is (10^-3.60) = 2.4E-4

Kb x Ka is 10^-14

Kb = 3.98E-11

Now we know Kb = [HA] [OH] / [A-]

Solve for this through algebra by using x for the values you dont know

youll find x^2 = 3.3E-10

X = 1.8 E -5

this is the OH- concentration

-log [oh] = pOH

pOH = 4.73

We know 14-pOH = ph so pH= 9.3

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3 years ago
What system is responsible for transporting food, waste, and gases throughout the body?
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Digestive I think, that transfers food.
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3 years ago
A sample of carbon dioxide occupies a 5.13 dm3 container at STP. What is the volume of the gas at a pressure of 286.5 kPa and a
suter [353]

Considering the ideal gas law and STP conditions, the volume of the gas at a pressure of 286.5 kPa and a temperature of 12.9°C is 1.8987 L.

<h3>Definition of STP condition</h3>

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

<h3>Ideal gas law</h3>

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

  • P is the gas pressure.
  • V is the volume that occupies.
  • T is its temperature.
  • R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.
  • n is the number of moles of the gas.  

<h3>Volume of gas</h3>

In first place, you can apply the following rule of three: if by definition of STP conditions 22.4 L are occupied by 1 mole of carbon dioxide, 5.13 L (5.13 dm³= 5.13 L, being 1 dm³= 1 L) are occupied by how many moles of carbon dioxide?

amount of moles of carbon dioxide=\frac{5.13 Lx1 mole of carbon dioxide}{22.4 L}

<u><em>amount of moles of carbon dioxide= 0.229 moles</em></u>

Then, you know:

  • P= 286.5 kPa= 2.8275352 atm (being 1 kPa= 0.00986923 atm)
  • V= ?
  • T= 12.9 C= 285.9 K (being 0°C= 273 K)
  • R= 0.082 \frac{atmL}{mol K}
  • n= 0.229 moles

Replacing in the ideal gas law:

2.8275352 atm× V = 0.229 moles×0.082 \frac{atmL}{mol K} × 285.9 K

Solving:

V= (0.229 moles×0.082 \frac{atmL}{mol K} × 285.9 K)÷ 2.8275352 atm

<u><em>V= 1.8987 L</em></u>

Finally, the volume of the gas at a pressure of 286.5 kPa and a temperature of 12.9°C is 1.8987 L.

Learn more about

STP conditions:

brainly.com/question/26364483

brainly.com/question/8846039

brainly.com/question/1186356

the ideal gas law:

brainly.com/question/4147359

#SPJ1

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