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mihalych1998 [28]
3 years ago
12

Which overall chemical equation is obtained by combining these intermediate equations?

Chemistry
1 answer:
Juli2301 [7.4K]3 years ago
5 0
The common substance among the product(s) of the first equation and among the reactant(s) in the second equation is H2O(g). We can eliminate that as an intermediate. The overall chemical equation will thus be:

CH4(g) + 2O2(g) → CO2(g) + 2H2O(l),

which is the first answer choice.

In essence, all you’re doing here is swapping water vapor for liquid water.
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Which of the following wouldn't be a good tool to use when measuring pH values of solutions?
aev [14]

litmus paper

Because it will just tell if the solution is acidic or basic, it won't tell the pH

4 0
3 years ago
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What volume of carbon dioxide gas can be collected from
alisha [4.7K]

Answer:

1.22 L of carbon dioxide gas

Explanation:

The reaction that takes place is:

  • CaCO₃ + HCl → CaCl₂ + CO₂ + H₂O

First we <u>determine which reactant is limiting</u>:

  • Calcium carbonate ⇒ 10.0 g CaCO₃ ÷ 100 g/mol = 0.10 mol CaCO₃
  • Hydrochloric acid ⇒ 0.100 L * 0.50 M = 0.05 mol HCl

So HCl is the limiting reactant.

Now we calculate the moles of CO₂ produced:

  • 0.05 mol HCl * \frac{1molCO_{2}}{1molHCl} = 0.05 mol CO₂

Finally we use PV=nRT to <u>calculate the volume</u>:

  • P = 1 atm
  • n = 0.05 mol
  • T = 25 °C ⇒ 25 + 273.16 = 298.16 K

1 atm * V = 0.05 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

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7 0
3 years ago
Liters of a 2.40 M
kotykmax [81]

Answer:

1.42 L

Explanation:

Step 1:

The following data were obtained from the question :

Molarity of KBr = 2.40 M

Mole of KBr = 3.40 moles

Volume of solution =?

Step 2:

Determination of the volume of the solution.

Molarity of solution is simply the mole of the solute per unit volume the of solution. It is given as :

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 3.4/2.4

Volume = 1.42 L

Therefore, the volume of the solution is 1.42 L

6 0
3 years ago
How much heat is given off when 869 g iron bar cools from 94 degrees celsius to 5
melomori [17]

Answer:

Heat given off was -34.34kJ

Explanation:

Mass of iron bar = 869g

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Final temperature (T2) = 5°C

Specific heat capacity of iron (c) = 0.444J/g°C

Heat energy (Q) = Mc∇T

Q = heat energy

c = specific heat capacity

∇T = change in temperature

M = mass of the substance

Q = mc∇T

∇T = T2 - T1

Q = Mc(T2 -T1)

Q = 869 * 0.444 * (5 - 94)

Q = 385.836 * -89

Q = -34339.404J

Q = -34.34kJ

The heat given of was -34.34kJ

4 0
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