To go from molecules, we first need to convert to moles and then convert to grams.
To convert from molecules to moles, we need to divide by Avogadro's constant.
1.15*10^21 molecules * (1 mole/6.022*10^23 molecules) = 0.0019097 moles
To convert from moles to grams, we need to use the molar mass.
The molar mass of P₂O₅ is (2*30.98)+(5*16.00) = 141.96
You can find the molar mass using the periodic table.
0.0019097 moles * (141.96 grams/1 mole) = 0.2711 grams.
Since we have 3 significant digits in 1.15*10^21, that means our final answer is limited to 3 significant digits.
Your final answer is 0.271 grams.
The initial equation is <span>F = (9/5)C + 32. We are asked to get the formula to solve for C. So the idea here is to isolate C on the other side, where F is currently located.
1. Subtract 32 on both sides.
2. Divide 9/5 on both sides.
You should get </span><span>C = 5 over 9(F – 32) as your answer. </span>
Answer:
D. It contains a phosphate with higher phosphoryl transfer potential than ATP
Explanation:
1,3-Bisphosphoglycerate contains a phosphate group that has high phosphoryl transfer potential than ATP (they can transfer the phosphoryl group to ATP). Other high phosphoryl transfer potential groups include :Creatine kinase and phosphoenolpyruvate.
Answer:
3-
Explanation:
Sodium aurothiosulfate is a salt with the formula Na₃Au(S₂O₃)₂. The cation of the salt is sodium ion, and the anion is aurothiosulfate ion. We can determine the charge of the aurothiosulfate ion, considering that the sum of the positive and negative charges must be equal to the charge of the compound, which is zero.
3 × Na⁺ + 1 × Au(S₂O₃)₂ⁿ⁻ = 0
3 × +1 + 1 × Au(S₂O₃)₂ⁿ⁻ = 0
Au(S₂O₃)₂ⁿ⁻ = 3-
Find the number of moles of sodium you have:
<span>n = m/M where m is your 20g of sodium and M is 22.99 g/mol. </span>
<span>Look at the stoichiometry of the equation - it's 2:2 when you are producing NaOH. So if you took 1 mole of Na, it'd produce 1 mole of NaOH (as the ratio is equal). </span>
<span>That means that your moles of sodium is equal to the moles of NaOH produced. Use the molar mass of NaOH - which is 39.998 g/mol along with your calculated number of moles to get the mass (the formula rearranges to m = nM). </span>
<span>This figure is the theoretical yield - what you would get if every last mole of sodium was converted into NaOH. </span>
<span>What you get in practice is the experminetal yield, and the percentage yield is the experimental yield divided by the theoretical yield - and then multiplied by 100%.</span>
