Answer:
Explanation:
The question relates to motion on a circular path .
Let the radius of the circular path be R .
The centripetal force for circular motion is provided by frictional force
frictional force is equal to μmg , where μ is coefficient of friction and mg is weight
Equating cenrtipetal force and frictionl force in the case of car A
mv² / R = μmg
R = v² /μg
= 26.8 x 26.8 / .335 x 9.8
= 218.77 m
In case of moton of car B
mv² / R = μmg
v² = μRg
= .683 x 218.77x 9.8
= 1464.35
v = 38.26 m /s .
Answer:
Current, I = 1.08 A
Explanation:
Given that,
Length of the copper wire, l = 12 cm = 0.12 m
Mass of the wire, m = 16 g = 0.016 kg
Magnetic field, B = 1.2 T
The magnetic field is oriented perpendicular to the wire. We need to find the current in the wire.
Magnetic force, F = BIL
Force of gravity, F' = mg
F' = F
I = 1.08 A
So, the current through the wire is 1.08 A. Hence, this is the required solution.
Answer:
For 9 is 2,4,1 and 3.For 10 b-c moves 15 from each other and e-f moves 15 also from each other.
Answer:
a) 360W
b) 0.36 J
c) 0.0008 C
Explanation:
1 ms = 0.001 s
a) The power is the product of current and potential difference
P = VI = 450 * 0.8 = 360 W
b) The energy is the power multiplied by time duration
E = Pt = 360*0.001 = 0.36 J
c) The total charge is the current multiplied by the time duration
C = It = 0.8*0.001 = 0.0008 C
Answer:
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