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BARSIC [14]
3 years ago
8

Draw structure for each of the following a) m-Xylene b) o-Cresol c) 3-Bromo-4-nitrobenzenesulfonic acid

Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
8 0

Answer:

Explanation:

a) m-Xylene

It is an aromatic hydrocarbon having molecular formula, C8H10. in this compound, two methyl groups are present at 1 and 3 positions of benzene ring.

b) o-Cresol

It is an organic compound having molecular formula, C7H8O. It is a substituted phenol in which a methyl group is present at ortho position.

c) 3-Bromo-4-nitrobenzenesulfonic acid

In this aromatic compound, three functional groups: -SO3H, -NO2 and -Br are present on the benzene ring at 1, 4 and 3 postion respectively.

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A sample containing 16.93 metal pellets is poured into a graduated cylinder containing 11.2 of water, causing the water level in
mixer [17]

Answer:

<h3>The answer is 1.99 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 16.93 g

volume = final volume of water - initial volume of water

volume = 19.7 - 11.2 = 8.5 mL

We have

density =  \frac{16.93}{8.5}  \\  = 1.9917647058...

We have the final answer as

<h3>1.99 g/mL</h3>

Hope this helps you

7 0
3 years ago
3. How much energy is needed to raise 45 grams of water from 40°C to 115 °C?
Dafna1 [17]

Answer:

Q = 114349.5 J

Explanation:

Hello there!

In this case, since this a problem in which we need to calculate the total heat of the described process, it turns out convenient to calculate it in three steps; the first one, associated to the heating of the liquid water from 40 °C to 100 °C, next the vaporization of liquid water to steam at constant 100 °C and finally the heating of steam from 100 °C to 115 °C. In such a way, we calculate each heat as shown below:

Q_1=45g*4.18\frac{J}{g\°C}*(100\°C-40\°C)=11286J\\\\Q_2=45g* 2260 \frac{J}{g} =101700J\\\\Q_3=45*2.02\frac{J}{g\°C}*(115\°C-100\°C)=1363.5J

Thus, the total energy turns out to be:

Q_T=11286J+101700J+1363.5J\\\\Q_T=114349.5J

Best regards!

5 0
3 years ago
Why must the spot applied to a TLC plate be above the level of the developing solvent? What problem will ensue if the level of t
algol13

Answer:

See explanation

Explanation:

If the spot in TLC is below the solvent front, it will be observed that the spot, instead of being separated by the solvent as expected, will just dissolve away in the solvent and zero actual separation of the mixture is achieved.

If the solute is dissolved away instead of being separated by the solvent, then the experiment fails because no actual separation of the mixture is achieved.

Hence, in TLC, the spot must be applied above the solvent front so that the capillary movement of the solvent through the plate can lead to the eventual separation of the components of the mixture since the various components of the mixture will travel at different speeds through the plate.

Also, if the solvent is above the spot, the solvent may evaporate selectively from the points above the spot while separation is ongoing.

6 0
3 years ago
Ok, I need help with this one!!!!!!!!!!!!!!!!!!!! plz and thank you
Kitty [74]

Answer:

D)

Explanation:

3 0
3 years ago
Which is more polar: carbon disulfide or sulfur difluoride
Ilya [14]
<span>Carbon disulfide. hope that helped</span>
4 0
3 years ago
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