1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lesya692 [45]
3 years ago
15

During a race, four competitors of the same weight rode identical bicycles for 10 minutes. At 8 minutes, which bicycle was movin

g with the greatest velocity?
Physics
1 answer:
Sophie [7]3 years ago
6 0

Answer:

All the competitors will move with the same velocity.

Explanation:

Here, the situations for each competitor are identical. Thus, they will exert the same force and hence, their velocities at each instants will be identical.

You might be interested in
An air bubble at the bottom of a lake 36.0 m deep has a volume of 1.22 cm^3. If the temperature at the bottom is 5.9°C and at th
AlexFokin [52]

Answer:

volume of the bubble just before it reaches the surface is 5.71 cm³

Explanation:

given data

depth h = 36 m

volume v2 = 1.22 cm³ = 1.22 × 10^{-6} m³

temperature bottom t2 = 5.9°C = 278.9 K

temperature top  t1 = 16.0°C = 289 K

to find out

what is the volume of the bubble just before it reaches the surface

solution

we know at top atmospheric pressure is about P1 = 10^{5} Pa

so pressure at bottom P2 = pressure at top + ρ×g×h

here ρ is density and h is height and g is 9.8 m/s²

so

pressure at bottom P2 = 10^{5} + 1000 × 9.8 ×36

pressure at bottom P2 =4.52 × 10^{5}  Pa

so from gas law

\frac{P1*V1}{t1} = \frac{P2*V2}{t2}

here p is pressure and v is volume and t is temperature

so put here value and find v1

\frac{10^{5}*V1}{289} = \frac{4.52*10^{5}*1.22}{278.9}

V1 = 5.71 cm³

volume of the bubble just before it reaches the surface is 5.71 cm³

6 0
3 years ago
You ride your skateboard to school and tell all your friends you rode at speed of 25 miles per hour
Ray Of Light [21]
And they think you're cool
5 0
3 years ago
Find the work w1 done on the block by the force of magnitude f1 = 75.0 n as the block moves from xi = -1.00 cm to xf = 3.00 cm .
MissTica
<span>The work done is 3.0 Nm. We can us the equation Work = Force * Distance, where Force = 75.0 N, and distance is xf – xi = 3.00 cm - -1.00 cm = 4.00 cm. Convert centimeters to meters by moving the decimal place to the left by two places to get 0.04 m. Plug these values into the Work equation: Work = Force * Distance Work = 75.0 N * 0.04 m Work = 3.0 Nm</span>
5 0
3 years ago
One of the main differences between the intaglio and the relief printing processes is that with intaglio the ink ________ the su
TEA [102]
The answer to this question is "LIES BELOW THE SURFACE" happens or occurs. When one of the main differences between the two which is the Intaglio and the other one is the relief printing processes is that with the Intaglio the ink LIES BELOW the surface of the printing plate.
5 0
3 years ago
Jeff is part of a trekking team. As he climbs a hill, he drops his water bottle, which has a mass of 0.25 kilograms. The bottle
eduard
Hope this helps you.

6 0
3 years ago
Read 2 more answers
Other questions:
  • If you compare an electrical circuit to a system that carries water, what would the switch represent?
    15·1 answer
  • Which of the following people would make the best scientist?
    14·2 answers
  • The picture above shows a football player kicking a football. This is known as two dimensional motion. In which direction does t
    7·1 answer
  • The car A has a weight of 4000 lb and is traveling to the right at 3 ft/s. Meanwhile a 2000 lb car B is traveling at 6 ft/s to t
    14·1 answer
  • SOLVE THE PROBLEM
    5·1 answer
  • What is transmitted by EM waves?
    11·1 answer
  • Difference between effort distance and load distance​
    14·1 answer
  • Question 4
    11·2 answers
  • A 0.137 kg mass on a string
    5·1 answer
  • Energy travels at right angles to the direction of the vibrating particles in ________ waves.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!