The sp hybridization of the central nitrogen is consistent with the linear structure of the azide ion. In A, the terminal nitrogens may both be sp2 hybridized; after all the drawing looks similar to the double bond in ethylene.
Answer:
615 g
Explanation:
In order to convert from moles of any given substance into grams, we have to use said substance's <em>molar mass</em>, as follows:
- # moles * Molar mass = grams of substance.
Thus, we now <u>calculate the molar mass of beryllium iodide</u>, BeI₂, using the <em>molar masses of the elements</em>:
- Molar Mass of BeI₂ = Molar Mass of Be + (Molar Mass of I)*2 = 262.821 g/mol
Finally we <u>calculate how many grams are there in 2.34 moles of BeI₂</u>:
- 2.34 mol * 262.821 g/mol = 615 g
Answer:
D. 0.4 (mol/L)/S
Explanation:
You simply have to plug in the given values into the rate law.
Rate = k[A][B]
Rate = (0.1)(1)²(2)²
Rate = (0.1)(1)²(4)²
Rate = 0.4
Answer:
Striped should be the answer
Answer:
butyne
Explanation:
alkane, alkene, and alkyne are all examples of hydrocarbons.
butyne = alkyne
