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Oksanka [162]
3 years ago
10

The part of an atom that is responsible for the bonding of atoms is —

Chemistry
1 answer:
kvv77 [185]3 years ago
7 0

Answer:

B

Explanation:

Valence electrons only involve in chemical bonding, since they are farthest from the nucleus. Hope this helps!

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A reaction that involves reagent X as the limiting reagent is begun with an initial concentration of 0.732-M X. The reaction rea
katovenus [111]

Answer:

The answer to the question is 0.0122 m/s

Explanation:

The rate of a reaction is the measure of the change in concentration of a reagent within a specific time frame. Reaction rate of a substance can be calculated by finding the division of the concentration change of the substance and the time required to undergo the change in concentration.

Average reaction rate \frac{Change in the moles count of X}{Change in time} =

The initial number of moles of X = 0.732 moles and final number of moles of X  = 0 moles and the time it took to effect the change = 60s

then the rate of reaction = \frac{0.732}{60} = 0. 0122 moles per second

the rate of the reaction involving X = 0.0122 m/s

7 0
4 years ago
Which of the following is the correct abbreviation for the air mass at point C in the diagram below?MT
erma4kov [3.2K]

Answer:

mP C. Is right

Explanation:

8 0
3 years ago
Read 2 more answers
1.00 g of a compound is combusted in oxygen and found to give 3.14g of CO2 and 1.29 g of H2O. From these data we can tell thatA.
lora16 [44]

Answer:

the compound contains C, H, and some other element of unknownidentity, so we can’t calculate the empirical formula

Explanation:

Mass of CO2 obtained = 3.14 g

Hence number of moles of CO2 = 3.14g/44.0 g = 0.0714 mol

The mass of the carbon in the sample = 0.0714 mol × 12.0g/mol = 0.857 g

Mass of H2O obtained = 1.29 g

Hence number of moles of H2O = 1.29g/18.0 g = 0.0717 mol

The mass of the carbon in the sample = 0.0717 mol × 1g/mol = 0.0717 g

% by mass of carbon = 0.857/1 ×100 = 85.7 %

% by mass of hydrogen = 0.0717/1 × 100 = 7.17%

Mass of carbon and hydrogen = 85.7 + 7.17 = 92.87 %

Hence, there must be an unidentified element that accounts for (100 - 92.87) = 7.13% of the compound.

5 0
3 years ago
How many moles of O, will occupy 1.00 L at a temper-
Kay [80]

Moles of O₂ = 3.92

<h3>Further explanation</h3>

Given

V=1 L

T=-118 °C + 273 = 155 K

P = 49.77 atm

Required

moles of O₂

Solution

the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

Input the value :

n= PV/RT

\tt n=\dfrac{49.77~atm\times 1~L}{0.082\times 155}=3.92~moles

7 0
3 years ago
The illustration above represents what concept?
Nitella [24]

Answer:

3 Is D

Explanation:

6 0
3 years ago
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