Answer:
B - The energy of reactants is conserved.
D - the nuclei of atoms changes completely ( if that's the option)
Answer:- cell potential = -0.19 volts
Solution:- The equation that shows the connection between
and cell potential, E is written as:

in this equation, n stands for moles of electrons, E stands for cell potential and F stands for faraday constant and it's value is
.
It asks to calculate the value of E, so let's rearrange the equation:

Let's plug in the values in it:


since, 
Where C stands for coulombs and V stands for volts.
So, 
E = -0.19 V
So, the cell potential is -0.19 volts.
Answer:
The binding energy released is 1.992 X 10⁻¹⁸ J
Explanation:
Given;
mass of the alpha particle, m = 6.64 x 10⁻²⁷ kg
speed of the alpha particle, c = 3 x 10⁸ m/s
The binding energy released is given by;

where;
m is mass of the particle
c is speed of the particle
E = 6.64 x 10⁻²⁷ (3 x 10⁸)²
E = 1.992 X 10⁻¹⁸ J
Therefore, the binding energy released is 1.992 X 10⁻¹⁸ J