Answer:
Q=msΔT
rearranging in terms of temperature gives:
ΔT=Q/ms
=1320j/(230g×0.338(j/g°C))
=16.97967584°C
=> ΔT=17.0°C
Answer:
8.73 L
Explanation:
First, you need to convert grams to moles using the molar mass.
Molar Mass (N₂): 2(14.009 g/mol)
Molar Mass (N₂): 28.018 g/mol
12.2 grams N₂ 1 mole
---------------------- x ------------------------ = 0.435 moles N₂
28.018 grams
To find the volume, you need to use the Ideal Gas Law:
PV = nRT
In this equation,
-----> P = pressure (torr)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas constant (62.36 torr*L/mol*K)
-----> T = temperature (K)
After converting the temperature from Celsius to Kelvin, you can plug the given values into the equation.
P = 1132 torr R = 62.36 torr*L/mol*K
V = ? L T = 91 °C + 273.15 = 364.15 K
n = 0.435 moles
PV = nRT
(1132 torr)V = (0.435 moles)(62.36 torr*L/mol*K)(364.15 K)
(1132 torr)V = 9888.015
V = 8.73 L
Answer:
The glassware and solvent for the production of grignard reagent and its reaction should by dry and anhydrous so as to prevent the conversion of the grignard reagent into saturated alkane. Acetone, is not a good solvent for the generation of grignard reagent because it has the potential of forming alcohol.
Explanation:
Grignard reagent is a compound formed by the reaction of halide of alkyl or alkene with magnesium metal. This makes the compound more nucleophilic. Thus the availability of an electrophile around it will evoke a quick reaction. The presence of water in an acidic condition will generate hydroxonium ions which are highly electrophilic. There will therefore be an introduction of hydrogen ions to the grignard reagent and which will displace the MgBr leading to the formation of alkane.
Acetone tends to produce alcohol when they are exposed to grignard reagent, thus they are not appropriate to be used as solvent. This is due to the resultant highly electrophilic nature of the carbonyl carbon on the acetone, thus will react with the nucleophilic carbon on the grignard. The reaction can be represented as follows:
RMgBr + CH3(CO)CH3 + H (with hydrogen ions) >>>RCOH + Mg(OH)Br
The symbol is ba. The number of neutrons equal the number of protons
The answer is C. Aluminium since it is highly reactive
