All categories

3 years ago

2. What is the surface area of the triangular prism below?

Mathematics

1 answer:

grandymaker [24]3 years ago

6 0

2 x Area of the triangular ends.
= 2 x ( 1/2 bh)
= 2 x (1/2 x 6.8 x 5.1)

2 x Area of rectangular sides
= 2 x lw
2 x (6.1 x 13)

Area of bottom
= lw
= 6.8 x 13

Now add all three results together for the surface area.

You might be interested in

Multiply 35×40 what equals

Vinil7 [7]

When you multiply 35 x 40 = 1400

:)

3 0

3 years ago

Which is a simplified form of the expression 3(m + 1) + 2m?

kompoz [17]

Answer:

D, 5m+3

PLEASE MARK BRAINLIEST

Step-by-step explanation:

Distribute:

=(3)(m)+(3)(1)+2m

=3m+3+2m

Combine Like Terms:

=3m+3+2m

=(3m+2m)+(3)

=5m+3

4 0

3 years ago

Read 2 more answers

Can i get someones help on this question

Setler [38]

Answer: I think the answer would be -4

4 0

2 years ago

Read 2 more answers

Two right triangles are shown below.

VladimirAG [237]

Answer:

the correct answer is C

7 0

3 years ago

Read 2 more answers

Integrate the following w.r.t x 1) 2x^2/3. <br>2) (5-x)^23<br>

Kryger [21]

Answer:

A) $\int\frac{2x^2}{3}dx=\frac{2x^3}{9}+C$

B) $\int(5-x)^{23}dx=-\frac{(5-x)^{24}}{24}+C$

Step-by-step explanation:

So we have the integral:

$\int\frac{2x^2}{3}dx$

First, remove the constant multiple:

$=\frac{2}{3}\int x^2\dx$

Use the power rule, where:

$\int x^ndx=\frac{x^{n+1}}{x+1}$

Therefore:

$\frac{2}{3}\int x^2\dx\\=\frac{2}{3}(\frac{x^{2+1}}{2+1})$

Simplify:

$=\frac{2}{3}(\frac{x^{3}}{3})$

And multiply:

$=\frac{2x^3}{9}$

And, finally, plus C:

$=\frac{2x^3}{9}+C$

We have the integral:

$\int(5-x)^{23}dx$

To solve, we can use u-substitute.

Let u equal 5-x. Then:

$u=5-x\\du=-1dx$

So:

$\int(5-x)^{23}dx\\=\int-u^{23}du$

Move the negative outside:

$=-\int u^{23}du$

Power rule:

$=-(\frac{u^{23+1}}{23+1})$

Add:

$=-(\frac{u^{24}}{24})$

Substitute back 5-x:

$=-(\frac{(5-x)^{24}}{24})$

Constant of integration:

$=-\frac{(5-x)^{24}}{24}+C$

And we're done!

8 0

3 years ago