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3 years ago

6

An animal shelter has 21 puppies if the puppies are 28% of the total dog and cat population how many dogs and cats are there in

the animal shelter A.59
B.70
C.49
D.75

1 answer:

Step2247 [10]3 years ago

8 0

D is the awnser to that question

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at a basketball game, a vendor sold a combined total of 218 sodas and hotdogs. The number of hotdogs sold was 50 less than the n

velikii [3]

9514 1404 393

Answer:

134 soda
84 hot dogs

Step-by-step explanation:

Let s represent the number of sodas sold. Then the number of hot dogs sold is (s-50) and the total is ...

s +(s -50) = 218

2s = 268 . . . . . . . . . add 50

s = 134 . . . . . . . divide by 2

134 sodas were sold; 84 hot dogs were sold.

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3 years ago

La ecuación h(x) =23 es lineal?

NARA [144]

Si! H(x)=23 es lineal

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2 years ago

Is (-6,7) a solution to this system of inequalities? <br> Y> -x + 1<br> Y > 1/3x -9

Firlakuza [10]

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3 years ago

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C is more than half of n

ycow [4]

Ummm What? soooo what are you looking for? if N is 8 that means C is larger than four. if you want an equation then here you go.

C > N/2

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3 years ago

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Drag the tiles to the correct boxes to complete the palrs.

Brut [27]

Answer:

(f+g)(2) = 4

(f-g)(4) = 8

(f ÷g)(2) = 7

(f x g)(1) = 0

Step-by-step explanation:

We are given these following functions:

$f(x) = 2x + 3$

$g(x) = x - 1$

(f+g)(2)

$(f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2$

At $x = 2$

$(f+g)(2) = 3(2) - 2 = 6 - 2 = 4$

Then

(f+g)(2) = 4

(f-g)(4)

$(f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4$

At x = 4

$(f-g)(4) = 4 + 4 = 8$

Then

(f-g)(4) = 8

(f ÷g)(2)

$(f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}$

At x = 2

$(f \div g)(2) = \frac{7}{1} = 7$

Then

(f ÷g)(2) = 7

(f x g)(1)

$(f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3$

Then

$(f \times g)(1) = 2(1)^2 + 1 - 3 = 3 + 1 - 3 = 0$

So

(f x g)(1) = 0

4 0

3 years ago