Potential Energy (Initial one) = m * g * h
P.E. = 60 * 9.8 * 10
P.E. = 5880
Kinetic Energy (Final One) = 1/2 mv²
K.E. = 1/2 * 60 * (10)²
K.E. = 6000/2
K.E. = 3000
Lost Energy = 5880 - 3000 = 2880 J
In short, Your Answer would be 2880 Joules
Hope this helps!
1 mA = 0.001 A
Therefore, 5 mA = 0.001 * 5
=0.005 A
Resistance = voltage / current
= 100 / 0.005
= 20000 ohms
Current = voltage / resistance
= 25 / 20000
= 0.00125 A (or) 1.25 mA
Answer:
True
Explanation:
The complete question is:
<em>"Although the reactions of the Calvin cycle do not depend directly on light, they do not usually occur at night. True o False"</em>
<em>
</em>The Calvin cycle is also known as the Calvin-Benson cycle or as the CO₂ fixation phase in the photosynthesis process.
The Calvin cycle generates the reactions necessary to fix the carbon in a solid structure for the formation of glucose and, in turn, regenerates the molecules for the continuation of the cycle.
The Calvin cycle is known as the dark phase of photosynthesis, or the carbon fixation phase. It is called the dark phase because this cycle is not dependent on light like other parts that make up the photosynthesis process. But it uses the energy that is produced in the light phase of photosynthesis to fix carbon.
It can be said that it consists of or forms the second stage of photosynthesis, in which the carbon of the carbon dioxide that is absorbed is fixed.
So, the statement is true because the Calvin cycle uses the energy that is produced in the light phase of photosynthesis to fix carbon.
The efficiency of the machine is defined as
Here
Work out is the work output and Work in is the work input
To find the Work in we have then
Replacing with our values
The work done by the applied force is
W = Fd
Here,
F = Force
d = Distnace
Rearranging to find F,
F = 129.77N
Therefore the force exerted on the machine after rounding off to two significant figures is 130N
