Fig. 4 shows a simply-supported beam with supports A and B. The beam is subjected to three forces, 2000 N, 4000 N and 1500 N in
1 answer:
You might be interested in
Answer:
The settling velocity of the particles (Vs) is greater than the overflow rate (V₀), thus the particles will settle out and will be removed.
Explanation:
Given;
volumetric flow rate of the treatment, Q₀ = 12,000 m³/day
length of the rectangular tank, L = 25 m
width of the tank, W = 12 m
height of the tank, H = 3 m
settling velocity of the particles, = 6 x 10⁻³ m/s
The overflow rate of the sediments are calculated as follows;
where;
As is the surface area of the tank, m²
Q₀ is the flow rate, m³/s
As = 2LW + 2LH + 2WH
As = (2 x 25 x 12) + (2 x 25 x 3) + (2 x 12 x 3)
As = 822 m²
The overflow rate;
The settling velocity of the particles (Vs) is greater than the overflow rate (V₀), thus the particles will settle out and will be removed.
Answer:
The valve should be closed at 1081 kPa ⇒ 11 bar
Explanation:
Therefore, v₂, u₂ fix state 2.
By trial and error, P₂ = 1081 kPa & T₂ = 50.4° C
1081 kPa ⇒ 11 bar