Answer / Explanation:
To proper understand the answers that is given to the question, we need to understand some basic terms that has been used in the question.
Energy: This can be refereed to as the quantitative property that is transferred to an object for the purpose of the object working or to heat up the object. It can also be referred to as conserved quantity that is energy can be converted from one form or state to another but cannot destroyed.
Power: This can be defined as the rate of doing work or transferring heat per unit time from one state to another. The SI Units of power is watt which is equal to one joule per second.
Hence, the formula that links energy and power is:
Energy = Power x Time
Now. referring back to the question (a) asking how much energy do we save if we execute at the current speed and turn off the system when the computation is complete: The answer is = 50%. That is 50% of the energy is saved.
(b) If we recall the formula for calculating energy,
we have:
Energy = 1 /2 Load x V²
Changing the frequency does not affect the energy.However, it affects the power.
So therefore, the new energy is 1 / 2 Load x ( 1/2 V)² ,
reducing it to about 1 /4 of the old energy.
Answer:
The question is incomplete, below is the complete question
"The real power delivered by a source to two impedance, Z1=4+j5Ω and Z2=10Ω connected in parallel, is 1000 W. Determine (a) the real power absorbed by each of the impedances and (b) the source current."
answer:
a. 615W, 384.4W
b. 17.4A
Explanation:
To determine the real power absorbed by the impedance, we need to find first the equivalent admittance for each impedance.
recall that the symbol for admittance is Y and express as
Hence for each we have,
for the second impedance we have
we also determine the voltage cross the impedance,
P=V^2(Y1 +Y2)
The real power in the impedance is calculated as
for the second impedance
b. We determine the equivalent admittance
We convert the equivalent admittance back into the polar form
the source current flows is
Answer:
-2/√3 atan ((2t + 1)/√3) + C
Explanation:
∫ (t − 1) / (1 − t³) dt
Factor the difference of cubes:
∫ (t − 1) / ((1 − t)(1 + t + t²)) dt
Divide:
∫ -1 / (1 + t + t²) dt
-∫ 1 / (t² + t + 1) dt
Complete the square:
-∫ 1 / (t² + t + ¼ + ¾) dt
-∫ 4 / (4t² + 4t + 1 + 3) dt
-∫ 4 / ((2t + 1)² + 3) dt
If u = 2t + 1, du = 2 dt:
-∫ 2 / (u² + 3) du
Use an integral table, or use trigonometric substitution:
-2 (1/√3) atan (u/√3) + C
-2/√3 atan (u/√3) + C
Substitute back:
-2/√3 atan ((2t + 1)/√3) + C
Answer:
To run. The machine one at a time
Explanation:
Answer:
18. 24/8 = 3
19. 50/12 = 4 and one-sixth
20. 18/16 = 1 and one-eighth
Explanation: I’m good at math
