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lakkis [162]
3 years ago
12

What is MIDI in soumd and audio engineering ? ​

Engineering
1 answer:
maxonik [38]3 years ago
4 0
It’s a technical standard that describes a communication protocol, or Musical Instrument Device Interface.
You might be interested in
A bar of steel has the minimum properties Se = 40 kpsi, Sy = 60 kpsi, and Sut = 80 kpsi. The bar is subjected to a steady torsio
Lerok [7]

Answer:

Factor of safety against static failure = 2.097

Factor of safety against fatique failure = 1.6

Explanation:

Bending stress = 12 kpsi

Se = 40 kpsi,

Sy = 60 kpsi,

Sut = 80 kpsi

See the attached file  for explanation

6 0
3 years ago
A hospitality organization wants to clear an area of forestland to start a new hotel. The environmental activists have filed a c
o-na [289]

Answer:

B. Public

Explanation:

A ____________ is any group that has an actual or potential interest in or impact on an organization's ability to achieve its objectives.

a. People

b. Public

c. Profile

d. Pro-association

4 0
3 years ago
Compute the fundamental natural frequency of the transverse vibration of a uniform beam of rectanqular cross section, with one e
marshall27 [118]

Answer:

The natural angular frequency of the rod is 53.56 rad/sec

Explanation:

Since the beam is free at one end and fixed at the other hence the beam is a cantilevered beam as shown in the attached figure

We know that when a unit force is placed at the end of a cantilever the displacement of the free end is given by

\Delta x=\frac{PL^3}{3EI}

Hence we can write

P=\frac{3EI\cdot \Delta x}{L^3}

Comparing with the standard spring equation F=kx we find the cantilever analogous to spring with k=\frac{3EI}{L^3}

Now the angular frequency of a spring is given by

\omega =\sqrt{\frac{k}{m}}

where

'm' is the mass of the load

Thus applying values we get

\omega _{beam}=\sqrt{\frac{\frac{3EI}{L^{3}}}{Area\times density}}

\omega _{beam}=\sqrt{\frac{\frac{3\times 20.5\times 10^{10}\times \frac{0.1\times 0.3^3}{12}}{5.9^{3}}}{0.3\times 0.1 \times 7830}}=53.56rad/sec

8 0
3 years ago
Read 2 more answers
A system consists initially of nA moles of gas A at pressure p and temperature T and nB moles of gas B separate from gas A but a
Volgvan

Answer:

A) б = - R ( nA In Ya - nB In Yb )

B) s2 = ( nA + nB ) s( T,P )

C) No entropy will be produced

Explanation:

A) assuming ideal gas behavior the expression for entropy produced

for a closed system : s2 - s1 = б

where : s1 ( initial entropy ) = nA sA ( T, P ) + nB sB ( T, P )

s2 ( final entropy ) = nA sA ( T, YaP ) + nB sB ( T, YbP )

∴ б = - R ( nA In Ya - nB In Yb )

B) Given that

Ya and Yb are less than 1  respectively, hence the value of б  = positive

also assuming the gases are identical

s2 = ( nA + nB ) s( T,P )

C) No entropy will be produced when same gas at same temperature and same pressure are mixed

5 0
3 years ago
The torque required to drive a 40 mm diameter power screw having double square threads with a pitch of 6 mm is 1.0 kN-m. The fri
myrzilka [38]

Answer:

This is self locking.

Explanation:

Given that

Diameter d= 40 mm

Pitch (P)= 6 mm

Torque T= 1 KN.m

Friction(μ) = 0.1

Thread is double square.

Condition for self locking

\mu >tan\theta

tan\theta=\dfrac{L} {\pi d}

L= n x P

N= number of start

Here given that double start so n=2

L=2 x 6 = 12 mm

tan\theta=\dfrac{L} {\pi d}

tan\theta=\dfrac{12} {\pi \times 40}

tan\theta=0.095            (μ = 0.1)

\mu >tan\theta

So from we can that this is self locking.

6 0
3 years ago
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