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lakkis [162]
3 years ago
12

What is MIDI in soumd and audio engineering ? ​

Engineering
1 answer:
maxonik [38]3 years ago
4 0
It’s a technical standard that describes a communication protocol, or Musical Instrument Device Interface.
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The coupling is used to connect the two shafts together. Assuming that the shear stress in the bolts is uniform, determine the n
AleksAgata [21]

Answer:

n = 2r³/Rd²

Explanation:

See the attached file for the derivation.

8 0
3 years ago
Select the correct answer.
andreev551 [17]

Answer:

c

Explanation:

8 0
3 years ago
Read 2 more answers
From the isometric view orientation resource, what are the four typical characteristics of a front view?
Natasha_Volkova [10]

From an isometric view orientation resource, the four (4) typical characteristics of a front view include the following:

  1. The front view graphically shows the length and height of an object
  2. The front view has the least amount of hidden lines.
  3. The front view must be chosen first.
  4. The front view's orientation influences the other views.

<h3>What is an isometric sketch?</h3>

An isometric sketch is also referred to as an isometric drawing and it can be defined as a graphical (pictorial) representation of a physical object in technical and engineering drawings, especially by drawing all its three dimensions (3D) at full scale.

<h3>The five characteristics of isometric sketches.</h3>

In technical and engineering drawings, the five (5) characteristics of isometric sketches include the following:

  1. The final image isn't distorted.
  2. The image is in three dimensions (3D).
  3. The final image is drawn to full scale.
  4. The image are all uniformly foreshortened.
  5. They are drawn using vertical lines and horizontal lines.

From an isometric view orientation resource, the four (4) typical characteristics of a front view include the following:

  1. The front view graphically shows the length and height of an object
  2. The front view has the least amount of hidden lines.
  3. The front view must be chosen first.
  4. The front view's orientation influences the other views.

Read more on isometric sketches here: brainly.com/question/17275728

#SPJ1

7 0
2 years ago
he desk has a weight of 80 lb and a centerof gravity at G. Determine the initial acceleration of a desk when the man applies eno
-BARSIC- [3]

Answer:

N_a=\frac{45.04}{2}=22.52lb,N_b=\frac{67.48}{2} =33.74lb

Explanation:

Na and Nb are the vertical reactions on each of the two legs at A and at B

For the horizontal forces:

Fcos(30)-0.5N_a-0.5N_b=0\\0.5N_a+0.5N_b= Fcos(30)\\N_a+N_b= 2Fcos(30)

For the vertical forces:

N_a+N_b-Fsin(30)-75=0\\N_a+N_b=Fsin(30)+80

Therefore equating both equations:

2Fcos(30)=Fsin(30)+80\\F(2cos(30)-sin(30))=80\\F=\frac{80}{2cos(30)-sin(30)} =64.93N

After the desk star to slide:

sum of all vertical force = ma , therefore:

N_a+N_b-64.93sin(30)-80=0\\N_a+N_b=64.93sin(30)+80

sum of all horizontal force = ma

64.93cos(30)-0.2N_a-0.2N_b=\frac{80lb}{32.2ft/s^2}a\\ 0.2(N_a+N_b)=64.93cos(30)-\frac{80lb}{32.2ft/s^2}a\\N_a+N_b=\frac{64.93cos(30)-\frac{80lb}{32.2ft/s^2}a}{0.2}=324.65-12.42a

equating both equations:

324.65-12.42a=64.93sin(30)+80\\12.42a=324.65-64.93sin(30)-80\\12.42a=212.185\\a=17.08ft/s^2

From the moment equation:

4N_b-80(2)-64.93(3)=\frac{-80}{32.2} (17.08)(2)\\N_b=67.48lb

N_a=\frac{64.93cos(30)-\frac{80lb}{32.2ft/s^2}(17.08)}{0.2}-67.48 = 45.04lb

For each leg: N_a=\frac{45.04}{2}=22.52lb,N_b=\frac{67.48}{2} =33.74lb

7 0
3 years ago
The Reynolds number is the major parameter that relates fluid flow momentum to friction forces. How is the Reynolds number defin
fiasKO [112]

Answer:

Reynolds number determines whether a flow is laminar or turbulent flow.

Explanation:

Reynolds number is defined as ratio of inertia force to the viscous force. it is a dimension less  number. Reynolds number is used to describe the type of flow in a fluid whether it is laminar flow or turbulent flow. Reynolds number is denoted by Re.

When Reynolds number is in the range of 0 to 2000, the flow is considered to be laminar.

When Reynolds number is in the range of 2000 to 4000, the flow is considered to be transition.

And when Reynolds number is more than 4000, the flow is turbulent flow.

                     The boundary layer thickness for a fluid is given by

                                      δ = \frac{5\times x}{\sqrt{Re}}

where δ is boundary layer thickness

           x is distance from the leading edge

           Re is Reynolds number

Thus from the above boundary layer thickness equation, we can see that the boundary layer thickness varies inversely to square root of reynolds number.

8 0
3 years ago
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