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3 years ago

Write the Rate Law

Chemistry

1 answer:

Ivanshal [37]3 years ago

5 0

As we know that rate law expression is

$r = k { |a| }^{2} { |b| }^{2}$

(a)

$r = k { |o2| }^{1} { |no2| }^{2}$

(b)

$r = k { |cl2| }^{1}$

(c)

$r = k { |chcl3|}^{1} { |cl2| }^{1}$

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Why do chemical equations have to be equal

Darina [25.2K]

Answer:

Every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. Therefore, there must be the same number of atoms of each element on each side of a chemical equation.

Explanation:

YW :)

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3 years ago

What is the reaction for CL^2 + 2 KBr —> 2 KCL+Br^2 of 11 grams of potassium bromide?

mylen [45]

Answer:

All the amounts of reactants and products are:

KBr

11.0g (given)

0.0924 mol

Cl₂

0.0462 mol

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KCl

0.0924 mol

6.89 g

Br₂

0.0462 mol

7.39 g

Explanation:

1. Balanced chemical equation (given)

$Cl_2+2KBr\rightarrow 2KCl+Br_2$

2. Mole ratios

$\dfrac{1molCl_2}{2molKBr}$

$\dfrac{2molKCl}{2molKBr}$

$\dfrac{1molBr_2}{2molKBr}$

3. Molar masses

Molar mass Cl₂: 70.906g/mol

Molar mass KBr: 119.002 g/mol

Molar mass KCl: 74.5513 g/mol

Molar mass KBr: 159.808 g/mol

4. Convert 11 grams of potassium bromide to moles:

#moles = mass in grams / molar mass

#mol KBr = 11g / 119.002g/mol = 0.092435mol KBr

5. Use the mole ratios to find the amounts of Cl₂, KCl, and Br₂

a) Cl₂

$\dfrac{1molCl_2}{2molKBr}\times 0.092435molKBr=0.0462molCl_2$

$0.0462175molCl_2\times 70.906g/molCl_2=3.28gCl_2$

b) KCl

$\dfrac{2molKCl}{2molKBr}\times0.092435molKBr=0.0924molKCl$

$0.092435molKCl\times 74.5513g/molKCl=6.89gKCl$

c) Br₂

$\dfrac{1molBr_2}{2molKBr}\times 0.092435molKBr=0.0462molBr_2$

$0.0462175molBr_2\times 159.808g/molBr_2=7.39gBr2$

The final calculations are rounded to 3 sginificant figures.

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4 years ago

What is the equilibrium constant expression for the following reaction?

Gwar [14]

Answer:

Kc = [CO][Cl₂]/[COCl].

Kp = P(CO)P(Cl₂)/P(COCl).

Explanation:

For the balanced reaction:

COCl₂(g) ⇄ CO(g) + Cl₂(g).

The equilibrium constant can be expressed as concentration equilibrium constant (Kc) or pressure equilibrium constant (Kp).

The equilibrium constant is the ratio of the product of products concentrations to the product of the reactants concentrations.

Kc = [CO][Cl₂]/[COCl].

Kp = P(CO)P(Cl₂)/P(COCl).

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Answer:

When electrons are shared between two nonmetals, covalent bonds are formed.

Explanation:

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I think the answer is A. They observed the way the elements looked

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3 years ago