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3 years ago

Write the Rate Law

Chemistry

1 answer:

Ivanshal [37]3 years ago

5 0

As we know that rate law expression is

$r = k { |a| }^{2} { |b| }^{2}$

(a)

$r = k { |o2| }^{1} { |no2| }^{2}$

(b)

$r = k { |cl2| }^{1}$

(c)

$r = k { |chcl3|}^{1} { |cl2| }^{1}$

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Give the charge and full ground-state electron configuration of the monatomic ion most likely to be formed by the element. rb

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Actually Rb or Rubidium in zero state has the following electron configuration:

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With the kinetic energy of a sample increases the____ will also increase

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Answer:

Its Temperature.

Explanation:

Kinetic energy is the energy possessed by a body while in motion. Potential energy on the other hand is the energy possessed by a body based on its position.
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Copper can have improved wear resistance if alloyed with ceramic alumina, Al2O3. If a copper alloy has 7.7 wt % Al2O3, what is i

vitfil [10]

The composition in mol% of the elements are :

4.91% of Al₂O₃ in alloy
95.08% of Cu in alloy

Given data :

Weight percentage of copper alloy = 7.7 wt %

Assume weight of alloy = 100 grams

<h3>Applying the weight percentage </h3>

mass of Al₂O₃ in alloy = 7.7 gm

Mass of Cu in alloy = 100 - 7.7 = 92.3 gm

First step : calculate the mole of elements

i) moles of Al₂O₃ in alloy

= mass of Al₂O₃ in alloy / Atomic mass of Al₂O₃

= 7.7 gm / 102 gm/mol

= 0.075 mol

ii) moles of Cu in alloy

= mass of Cu in alloy / Atomic mass of Cu

= 92.3 gm / 63.5 gm/mol

= 1.45 mol

Therefore the total number of moles in the alloy = 0.075 + 1.45 = 1.525

Next step : Determine the mole percentages

i) Mole percentage of Al₂O₃ in alloy

= ( 0.075 ) / 1.525 * 100

= 4.91%

ii) Mole percentage of Cu in alloy

= ( 1.45 ) / 1.525 * 100

= 95.08%

Hence we can conclude that The composition in mol% of the elements are : 4.91% of Al₂O₃ in alloy and 95.08% of Cu in alloy.

Learn more about alloys : brainly.com/question/716507

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