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3 years ago

Write the Rate Law

Chemistry

1 answer:

Ivanshal [37]3 years ago

5 0

As we know that rate law expression is

$r = k { |a| }^{2} { |b| }^{2}$

(a)

$r = k { |o2| }^{1} { |no2| }^{2}$

(b)

$r = k { |cl2| }^{1}$

(c)

$r = k { |chcl3|}^{1} { |cl2| }^{1}$

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How many moles of calcium chloride would react with 5. 99 moles of aluminum oxide?

slega [8]

There are 17.97 moles of calcium chloride would react with 5. 99 moles of aluminum oxide .

The balanced chemical equation between reaction between calcium chloride and aluminum oxide is given as,

$3CaCl_{2} (aq)+Al_{2} O_{3} (s)$ → $3CaO_{2} (s)+2Al Cl_{3} (aq)$

The molar ratio of above reaction is 3:1

It means 3 moles of calcium chloride is require to react one mole of aluminum oxide.

The number of moles of calcium chloride requires to react with 5. 99 moles of aluminum oxide = 3 × 5. 99 = 17.97 moles

The equation in which number of atoms of elements in reactant side is equal to the number of atoms of elements in product side is called balanced chemical equation .

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2 years ago

HELP FAST 75 PTS Calculate the amount of heat needed to melt 35.0 g of ice at 0 ºC. must show work

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It takes 12,000 Joules of energy to melt 35 grams of ice at 0 °C

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3 years ago

Which phrase best describes the bond in H2?

Gala2k [10]

Answer and Explanation:

Two hydrogen atoms, each containing one electron, approach each other in the formation of a molecule of hydrogen. Each atom needs a total of two electrons to fill their outermost energy level and make them stable. The best choice is to share their single electrons. Hence, a pair of bonding electrons is shared between the hydrogen atoms in the molecules.

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Ancient Romans built often out of bricks and mortar. A key ingredient in their mortar was quicklime (calcium oxide), which they

velikii [3]

The question has missing information. At part 1 it is "Write a balanced chemical equation, including physical state symbols, for the decomposition of solid calcium carbonate (CaCO3) into solid calcium oxide and gaseous carbon dioxide."

Part 2. "Suppose 19.0 L of carbon dioxide gas are produced by this reaction, at a temperature of 290.0°C and pressure of exactly 1 atm. Calculate the mass of calcium carbonate that must have reacted (...)"

Answer:

41.0 g

Explanation:

1. Calcium oxide has molecular formula CaO and carbon dioxide CO₂, thus, the reaction will be:

CaCO₃(s) → CaO(s) + CO₂(g)

The equation is already balanced because there's the same number of each element on both sides.

2. First, let's calculate the number of moles of CO₂ produced by the ideal gas law:

PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.082 atm.L/mol.K), and T is the temperature (290°C = 273 = 563 K).

1*19 = n*0.082*563

46.166n = 19

n = 0.4116 mol

By the stoichiometry of the reaction:

1 mol of CaCO₃ ------ 1 mol of CO₂

x ----- 0.4116 mol

By a simple direct three rule:

x = 0.4116 mol of CaCO₃.

The molar mass of the calcium carbonate is 100 g/mol, thus the mass (m) is the number of moles multiplied by it:

m = 0.4116*100

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3 years ago

What mass of H2SO4 is contained in 60.00 mL of a 5.85 M solution of sulfuric acid

strojnjashka [21]

First, we have to calculate the number of moles of H2SO4 in the solution:

V=60 mL = 0.06 L

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n=V×c=0.06×5.85=0.351 mol

Then we need to find the molar mass of H2SO4:

2×Ar(H) + Ar(S) + 4×Ar(O) =

=2 + 32 + 64 = 98 g/mol

Finally, we need to find the mass of H2SO4:

m=0.351 × 98 = 34.398 g

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