All categories

2 years ago

A generator contains a coil that spins to produce an electric current. How is energy transformed by using a generator

Physics

1 answer:

LiRa [457]2 years ago

7 0

<u>Answer </u>

Mechanical energy ⇒ Electric energy

<u>Explanation </u>

A generator is used to produce electric energy. When he coils are made to rotate/spin, is makes the mechanical part. This coils rotates inside a magnetic fields inducing current in the coils. When current starts flowing in the coils, it forms the electrical part.

So, on the generator the energy changes are from mechanical to electrical energy.

You might be interested in

A car moving 12m east, then 20m west . What is the displacement?

Ludmilka [50]

Answer:

8 m west

Explanation:

If we say east is the +x direction, and west is the -x direction, then the displacement is:

Δx = 12 m + (-20 m)

Δx = -8 m

8 0

2 years ago

•. Parking orbit is -

notsponge [240]

Answer:

Parking orbit is -

a. The path along which a plane travels

b. Orbit of a polar satellite

c. Orbit of geostationary satellite

d. Orbit of the earth.

Explanation:

7 0

2 years ago

Read 2 more answers

1) Si un mango cae a una velocidad de 75m/s y tarda 26 seg. en caer. ¿ Cuál habrá sido la velocidad con qué el mango llegó al su

Lyrx [107]

Answer:

El mango llega al suelo a una velocidad de 329.982 metros por segundo.

Explanation:

El mango experimenta un movimiento de caída libre, es decir, un movimiento uniformemente acelerado debido a la gravedad terrestre, despreciando los efectos de la viscosidad del aire y la rotación planetaria. Entonces, la velocidad final del mango, es decir, la velocidad con la que llega al suelo, se puede determinar mediante la siguiente fórmula cinemática:

$v = v_{o}+g\cdot t$ (1)

Donde:

$v_{o}$ - Velocidad inicial, en metros por segundo.

$v$ - Velocidad final, en metros por segundo.

$g$ - Aceleración gravitacional, en metros por segundo al cuadrado.

$t$ - Tiempo, en segundos.

Si sabemos que $v_{o} = -75\,\frac{m}{s}$ , $g = -9.807\,\frac{m}{s^{2}}$ y $t = 26\,s$ , entonces la velocidad final del mango es:

$v = v_{o}+g\cdot t$

$v = -75\,\frac{m}{s}+\left(-9.807\,\frac{m}{s} \right)\cdot (26\,s)$

$v = -329.982\,\frac{m}{s}$

El mango llega al suelo a una velocidad de 329.982 metros por segundo.

8 0

2 years ago

Which type of evidence was used to tie Ted Bundy to the murder of Lisa Levy?

Elodia [21]

Explanation:

identified by one of the Chi Omega survivors as the assailant, and hair and fiber evidence tied him to the Leach murder. His trial for the Florida attacks in June 1979 was the first-ever nationally televised trial in the United States.

6 0

1 year ago

A merry-go-round with a a radius of R = 1.63 m and moment of inertia I = 196 kg-m2 is spinning with an initial angular speed of

Ulleksa [173]

Answer:

299.88 kgm²/s

499.758 kgm²/s

Explanation:

R = Radius of merry-go-round = 1.63 m

I = Moment of inertia = 196 kgm²

$\omega_i$ = Initial angular velocity = 1.53 rad/s

m = Mass of person = 73 kg

v = Velocity = 4.2 m/s

Initial angular momentum is given by

$L=I\omega_i\\\Rightarrow L=196\times 1.53\\\Rightarrow L=299.88\ kgm^2/s$

The initial angular momentum of the merry-go-round is 299.88 kgm²/s

Angular momentum is given by

$L=mvR\\\Rightarrow L=73\times 4.2\times 1.63\\\Rightarrow L=499.758\ kgm^2/s$

The angular momentum of the person 2 meters before she jumps on the merry-go-round is 499.758 kgm²/s

5 0

2 years ago