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3 years ago

Air leakage tests are conducted by using a large fan to blow air into a structure.

1 answer:

5 0

TRUE
An airtightness test it’s a whole building test that measures how easy it is for air to leak through a building enclosure or “skin” one common method is to use a large fan or “blower” to extract air from or supply air to the building.

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Given a 8-bit ripple carry adder and the following four input scenarios: (i) A4 + 1F, (ii) AB+55, (iii) CA+34, (iv) 6D+29. a) Un

Bogdan [553]

Answer:

Answer for the question:

Given a 8-bit ripple carry adder and the following four input scenarios: (i) A4 + 1F, (ii) AB+55, (iii) CA+34, (iv) 6D+29. a) Under which input scenario can adder generate correct output with the minimal delay? b) Under which input scenario can adder generate correct output with the maximum delay?

Is given in the attachment.

Explanation:

5 0

3 years ago

Read 2 more answers

The following figures were obtained in a standard tensile test on a specimen of low carbon steel with a circular sectional area:

liq [111]

Answer:

See Explaination

Explanation:

1)here for given stress strain curve graph is given as follows

where for getting stress,S=F/A=4F/(pi*(50*10^-3)^2)

for strain=e=dl/l=dl*10^-3/100 mm/mm or m/m

2)so graph is as follows

3)for getting youngs modulus of elasticity we must know slope of graph stress verses strain and for straight line in elastic region upto 12 point we have elastic region and from that we get E as

E=slope of graph for first 12 points=S/e=14.5665*10^9/.812=17.9390*10^9 N/m2

4)for getting ultimate tensile stress at which specimen bears maximum load without failure so we get UTS as

UTS=maximum load/area=40*10^6/1.9634=20.3728*10^6 N/m2

5)percentage reduction in area is given by

percentage reduction in area=[original area-final area/original area]*100

Percent reduction=[5062-10^2]*100/50^2=96%

6)percentage elongation is given by

percent elongation=[final length-original length/original length]*100

final length at fractureis=14.56+100=114.56 mm

so we get percent elongation as=[114.56-100/100]*100=14.56%

7)true fracture stress is given by load at fracture devided by true area at fracture

Sf=load/(true area)=4*28*10^3/(pi*(10*10^-3)^2)=356.5070*10^6 N/m2

8 0

4 years ago

A beam spans 40 feet and carries a uniformly distributed dead load equal to 2.2 klf (not including beam self-weight) and a live

salantis [7]

Answer:

A beam is a structural member that is subjected primarily to transverse loads ... stress equal to σy, then the section Moment - Curvature (M-φ) response for .... Example 2.2 Design a simply supported beam subjected to uniformly distributed dead ... (live load). • Step I. Calculate the factored design loads (without self-weight).

Explanation:

6 0

3 years ago

How do you remove a manual transmission?

Citrus2011 [14]

Answer:

Step 1

Elevate the front of the vehicle using the floor jack and support the vehicle with two jack stands. Make sure the vehicle is stable.

Step 2

Disengage all electrical components connected to the transmission. Indicate by marking the position of the drive shaft for its reinstallation. From the output shaft, remove the rear U joint. Jam the cloth to keep the liquid from dripping out of the extension housing.

Step 3

Loosen the shift linkages and the speedometer cable from the transmission manually. Place the transmission jack under the transmission, and then take a socket wrench and remove the support nut, the cross-member, and the rear support insulator from the rear engine. Support the engine with a jack stand and use the transmission jack to withdraw the transmission toward the rear of the vehicle.

Explanation:

4 0

4 years ago

An overhead 25m-long, uninsulated industrial steam pipe of 100-mm diameter, is routed through a building whose walls and air are

wariber [46]

Answer:

1) q=18414.93 W

2) C=12920$

Explanation:

Given data:

pipe length L=25m

pipe diameter D=100mm =0.1 m

air temperature $T_{s1}$ = $T_{\infty1} }$ =25 °C.....= 298.15k

pipe surface temp $T_{s2}$ =150 °C.....=423.15k

surface emissivity e= 0.8

boiler efficiency η=0.90

natural gas price Cg=$0.02 per MJ

1) Total heat loss and radiation heat loss combined

q= $q_{conv} +q_{rad}$

q= $A[h(T_{s2}-T_{s1})+e$ б( $T_{s2}$ ^4- $T_{s1}$ ^4)]....... (1)

б=5.67×10^-8 W/m^2K^4 (boltzmann constant)

area A =L.Dπ=25×0.1π=7.85 m^2

putting all these values in eq (1)

q=18414.93 W

2) suppose boiler is operating non stop annual energy loss will be

E=q.t

=18414.93.3600.24.365

=5.81×10^11 J

to find furnace energy consumption

Ef =E/η

=6.46×10^5 MJ

annual cost

C=Cg. Ef

=12920$

8 0

3 years ago