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DerKrebs [107]
3 years ago
5

Given a 8-bit ripple carry adder and the following four input scenarios: (i) A4 + 1F, (ii) AB+55, (iii) CA+34, (iv) 6D+29. a) Un

der which input scenario can adder generate correct output with the minimal delay? b) Under which input scenario can adder generate correct output with the maximum delay?

Engineering
2 answers:
Bogdan [553]3 years ago
5 0

Answer:

Answer for the question:

Given a 8-bit ripple carry adder and the following four input scenarios: (i) A4 + 1F, (ii) AB+55, (iii) CA+34, (iv) 6D+29. a) Under which input scenario can adder generate correct output with the minimal delay? b) Under which input scenario can adder generate correct output with the maximum delay?

Is given in the attachment.

Explanation:

Akimi4 [234]3 years ago
3 0

Answer:

With A4 + 1F input scenario, the adder can generate correct output with the minimal delay.

With AB + 55 input scenario, the adder can gcorrect output with the maximum delay.

Explanation:

A4 + 1F can be grounded to give the least significant bits and can generate correct output with the minimal delay, which AB + 55 can be grounded to give more significant bits(a0,b0) and can generate correct output with the maximum delay.

In 8-bit ripple carry adder. eight inputs a7 to a0 and b7 to b0 are applied to each of the full adder cell and output S7 to S0 represents eight bit sum from each full adder.

The input carry of the first half adder cell must be grounded for the correct addition of least significant bits (a0, b0) otherwise it will result in erroneous output

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navik [9.2K]

Answer:

Absolute pressure=70.72 KPa

Explanation:

Given that Vacuum gauge pressure= 30 KPa

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We know that P= ρ g h

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So P=13600 x 9.81 x 0.755

P=100.72 KPa

We know that

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3 years ago
Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If user
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Answer:

import java.util.Scanner;

public class FindMatchValue {

  public static void main (String [] args) {

     Scanner scnr = new Scanner(System.in);

     final int NUM_VALS = 4;

     int[] userValues = new int[NUM_VALS];

     int i;

     int matchValue;

     int numMatches = -99; // Assign numMatches with 0 before your for loop

     matchValue = scnr.nextInt();

     for (i = 0; i < userValues.length; ++i) {

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     }

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         numMatches = 0;

     for (i = 0; i < userValues.length; ++i) {

        if(userValues[i] == matchValue) {

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Sveta_85 [38]

Complete Question

The complete question is shown on the first uploaded image

Answer:

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Explanation:

The explanation is shown on the second third and fourth image

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