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goldfiish [28.3K]
3 years ago
10

Each of the following models represents particles present before and after a

Chemistry
1 answer:
lana [24]3 years ago
5 0

Answer:

D

Explanation:

According to the law of conservation of mass, matter can neither be created nor destroyed. The implication of this is that the total mass of reactants should be equal to the total mass of products.

There should be equal masses of reactants and products on both sides of the reaction equation. This most important condition is only satisfied by option D.

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"I think of a number, multiply it by itself and then add 6 to the result<br>+​
Sonja [21]

Answer:

ok 3 = 9 15 i got 15 so what

Explanation:

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Olivia bought new gym shoes to play volleyball because she kept slipping when she ran in her old shoes. How will the new soles h
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Maybe her old shoes had soft worn out bottoms and she slips in them. So her new shoes had more grip than her old ones so they kept her from falling.
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Question 25 of 33
Dafna11 [192]

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A) It tends to increase from top to bottom of a group

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Vitamin C, also known as ascorbic acid, is composed of 40.9 percent carbon, 4.6 percent hydrogen, and 54.5 percent oxygen. The m
Vladimir79 [104]

Answer:

Molecular formula is : C₆H₈O₆  

Explanation:

40.9 % of C, 4.6 % of H, 54.5 % of O means that in 100 g of ascorbic acid, we have 40.9 g of C, 4.6 g of H and 54.5 g of O.

If 1 mol of ascorbic acid weighs 176 g, let's determine the rules of three to know the grams of each element:

100 g of compound has ___ 40.9 g C __ 4.6 g H ___ 54.5 g O

176 g compound mus have:

(176 . 40.9) / 100 = 72 g of C

(176 . 4.6) / 100 = 8 g of H

(176 . 54.5) / 100 = 96 g of O

If we convert the mass to moles:

72 g . 1 mol / 12 g = 6 C

8 g . 1 mol/ 1g = 8 H

96 g . 1mol / 16 g = 6 O

Molecular formula is : C₆H₈O₆  

In conclussion, 1 mol of ascorbic acid has 6 moles of C, 8 moles of H and 6 moles of O

6 0
4 years ago
If 45.8 grams of potassium chlorate decomposes, how many grams of oxygen gas can be produced? 2KClO3 → 2KCl + 3O2
natta225 [31]
To do this problem, we must first look at the balanced chemical equation for the decomposition of potassium chlorate: 

<span>2KClO3 --> 2KCl + 3O2 </span>

<span>We can take the given amount of grams, and use the molar mass of KClO3 to convert to moles. Then, we can use the stoichiometric ratios to relate moles of KClO3 to moles of O2. </span>

<span>(39.09)+(35.45)+(3*15.99)= 122.51 g/ mol = molar mass of KClO3 </span>
<span>45.8 g KClO3/ 122.51 g/ mol KClO3 = .374 moles KClO3 </span>
<span>.374 mol KClO3 *(3 moles O2/2 mol KClO3)= .560 moles O2 </span>

<span>Once we have moles of O2, we can convert to grams of O2. </span>

<span>(2*15.99)= 31.98 g/mol = molar mass of O2 </span>
<span>(.560 moles O2) (31.98 g/mol)= 17.91 g O2 </span>


<span>Hope this helps :)</span>
3 0
3 years ago
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