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Sloan [31]
3 years ago
9

How do you find useful power?

Physics
1 answer:
antoniya [11.8K]3 years ago
6 0

Answer:  Calculating Mechanical Power as a Function of Work Calculate work.

Calculating Mechanical Power as a Function of Velocity Rewrite the formula for power.

Calculating Electrical Power Record the circuit’s voltage.nation:

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An electric field around two charged objects is shown.
mamaluj [8]

Answer: D

<u></u>

X: positive

Y: negative

Explanation:

It's either A or D and I chose A and got it wrong.

3 0
3 years ago
In an atomic clock there are approximately 9.193 × 109oscillations of the specified light emitted by cesium-133 atoms. The text
Aleks [24]

Explanation:

6000 years = 6000 x 365 x 24 x 60 x 60

= 1.892 x 10¹¹ second

 gain is 1 second

1 second is equivalent to 9.193 × 10⁹ oscillations .

In 1.892 x 10¹¹ second ,  change in oscillation is 9.193 × 10⁹ oscillation

in one second change in oscillation = (9.193 / 1.892 ) x 10⁹⁻¹¹

=  4.859 x 10⁻² oscillations .

5 0
2 years ago
When do you turn your wheels sharply left before backing slowly in a parallel parking maneuver?
Alex_Xolod [135]

Answer:

What is C - when your front bumper is even with the front vehicles back bumper.

Explanation:

Good Luck

8 0
2 years ago
A pebble is released from rest at a certain height and falls freely, reaching an impact speed of 6 m/s at the floor. Next, the p
Anna71 [15]

Answer:

Explanation:

Let h be the height .

initial velocity in first case u = 0

final velocity v = 6 m /s

acceleration due to gravity g = 9.8 m /s²

v² = u² + 2 g h

6² = 0 + 2 x 9.8 x h

h = 1.837 m .

For second case u = 3 m /s

v² = u² + 2 gh

= 3² + 2 x 1.837 x 9.8

= 9 + 36

= 45 m

v = 6.7 m /s

8 0
3 years ago
A block with m = 300 grams oscillates at the end of a linear spring with k = 6.5 N/m. (assume this is a top-down view and the bl
inna [77]

Answer:

a) T=1.35s

b) amplitude = 0.0923m

Explanation:

m=300 gr

k=6.5 N/m

first we need to get the angular frequency of the motion

so we have that

ω = √(k/m)

in this case motion is a simple harmonic so the period is defined by:

T= 2π / ω

T= 2π / √(k/m)

replacing the variables...

T= 2π / √(6.5/0.3)

T=1.35s   (period of the block's motion)

and...

α max = | ω²r max |

2 = (2π/1.35)² * r max

r max= 0.0923m

6 0
3 years ago
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