(2.03x10^22)/(6.02x10^23) = .033721 mol Li
I hope this helps, if not, i am sorry
Answer is: the energy of exactly one photon of this light is 4.75·10⁻¹⁹ J.
Photon energy equation: E = h·ν.
E - energy of one photon.
ν- frequency.
h - Planck's constant.
ν = 7.17·10¹⁴ Hz.
h = 6.63·10⁻³⁴ J·s.
E = 6.63·10⁻³⁴ J·s · 7.17·10¹⁴ Hz.
E = 4.75·10⁻¹⁹ J.
Answer:
Order of increasing strength of intermolecular attraction:
>
>
> Ar
Explanation:
can form hydrogen bond as H atom is attached with electronegative atom O.
Rest three,
,
, Ar are non-polar molecules.
In non-polar molecules, van der Waal's intermolecular forces of attractions exist. Hydrogen bonding is stronger intermolecular attraction then van der Waal's intermolecular forces of attraction, hence,
has strongest intermolecular attractions.
Ar will have least intermolecular attraction, as it behaves almost as ideal gas and there is no intermolecular attraction exist between molecules of ideal gases.
Molecular size and mass of
is high as compared to
.
van der Waals intermolecular forces of attraction increases with increase in size.
Therefore,
Order of increasing strength of intermolecular attraction will be:
>
>
> Ar
Answer:
n=6 to n=3 (B)
Explanation:
Energy of an electron present in the
orbit is directly proportional to
.Hence a transistion from one orbit to another orbit emits an energy proportional to the difference of their squares of the orbits. that is if an electron travels from orbit n1 to orbit n2 then it emits an energy corresponding to
.So in the above question the highest energy emission occurs when an electron moves from n=6 to n=3.(Highest difference of energy levels).