1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zubka84 [21]
3 years ago
9

8)

Physics
1 answer:
marishachu [46]3 years ago
6 0

Answer:

The box will experience an acceleration.

Explanation:

Here, 2 N and 3 N forces are acting opposite to each other. In this case, the net force experience by the box would be (3-2)N = 1 N towards right. Since acceleration is directly proportional to the net force, therefore the box will experience an acceleration.

You might be interested in
Learning Goal: To understand the distinction between mass and weight and to be able to calculate the weight of an object from it
Nimfa-mama [501]

Answer:

The true statements are: A, D

Explanation:

This interesting problem of the conceptual relationship between mass and weight, the equation for weight is

        W = m g

From Newton's second law

       W = ma

Where g the acceleration of gravity, this acceleration can vary at several points, for example, in a vertical circumference the acceleration of gravity is always down and the centripetal acceleration continuously changes direction therefore the body weight constantly changes from zero to the maximum value.

The mass instead is always the same and is the resistance (inertia) to the movement of the bodies

Of the aforementioned the peo has the unit mass multiplied by the acceleration

           

        Weight [N] = mass [kg] acceleration [m / s2]

        Weight [lb] = mass [slug] acceleration [ft / s2]

Examine the statements

A) 12.0 lb. True pounds are the mass for acceleration. English measurement system

B) 0.34g False. Grams are units of mass,

C) 120 kg. False. The kilograms is a multiple of the grams, which are units of mass

D) 1600 kN True the newton is the unit of weight, the Newton kilo is a multiple

E) 0.34 m False meters are units of length

F) 411 cm False centimeters is a submultiple of the meter that is a unit of length

The true statements are: A, D

4 0
3 years ago
You plan to take a trip to the moon. Since you do not have a traditional spaceship with rockets, you will need to leave the eart
hichkok12 [17]

Answer:

v = 3.5 \times 10^5 m/s

Explanation:

At some distance from the Earth the force of attraction due to moon is balanced by the force due to Moon

so we will have

\frac{GM_em}{r^2} = \frac{GM_m}{(d-r)^2}

now we have

\frac{d - r}{r} = \sqrt{\frac{M_m}{M_e}}

\frac{3.844\times 10^8 - r}{r} = \sqrt{\frac{7.36 \times 10^{22}}{5.9742\times 10^{24}}}

so we will have

r = 3.46 \times 10^8 m

Now by energy conservation

-\frac{GM_e}{R_e} - \frac{GM_m}{d - (R_e + R_m)} + \frac{1}{2}v^2 = -\frac{GM_e}{r} - \frac{GM_m}{d - r}

-6.26 \times 10^{8} - 13046 + \frac{1}{2}v^2 = -1.15 \times 10^6 - 1.28 \times 10^5

v = 3.5 \times 10^5 m/s

7 0
3 years ago
A 56 kg sprinter, starting from rest, runs 49 m in 7.0 s at constant acceleration.what is the sprinter's power output at 2.0 s,
alexgriva [62]
The sprinter is in uniform accelerated motion, and its initial velocity is zero, so the relationship betwen space (S) and time (t) is
S= \frac{1}{2} a t^2
where a is the acceleration. Using the data of the problem, we can find a:
a= \frac{2S}{t^2} = \frac{2 \cdot 49 m}{(7.0 s)^2} =2.0 m/s^2
So now we can solve the 3 parts of the problem.

a) power output at t=2.0 s
The velocity at t=2.0 s is
v(t)=at=(2.0 m/s^2)(2.0 s)=4.0 m/s

the kinetic energy of the sprinter is
K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(4.0 m/s)^2=448 J

and so the power output is
P= \frac{E}{t} = \frac{448 J}{2.0 s} =224 W

b) power output at t=4.0s 
The velocity at t=4.0 s is
v(t)=at=(2.0 m/s^2)(4.0 s)=8.0 m/s

the kinetic energy of the sprinter is
K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(8.0 m/s)^2=1792 J

and so the power output is
P= \frac{E}{t} = \frac{1792 J}{4.0 s} =448 W

c) Power output at t=6.0 s
The velocity at t=2.0 s is
v(t)=at=(2.0 m/s^2)(6.0 s)=12.0 m/s

the kinetic energy of the sprinter is
K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(6.0 m/s)^2=4032 J

and so the power output is
P= \frac{E}{t} = \frac{4032 J}{6.0 s} =672 W
8 0
3 years ago
PLEASE ANSWER!!! WILL GIVE BRAINLIEST!!!!!
Kipish [7]

Answer:

the ability to do work.

EXPLAINATION: .

in other words "the potential for causing changes" or "energy is the cause of any change" or "a work that a certain force *eg: gravitational* can do.

<em><u>sorry</u></em><em><u> </u></em><em><u>if</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>not</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>that</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>wante</u></em><em><u>d</u></em><em><u> </u></em><em><u>but</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>couldn't </u></em><em><u>under</u></em><em><u>stand</u></em><em><u> </u></em><em><u>your</u></em><em><u> </u></em><em><u>question</u></em><em><u> </u></em><em><u>that's </u></em><em><u>why</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>wrote</u></em><em><u> </u></em><em><u>what</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>understood</u></em><em><u>.</u></em>

6 0
2 years ago
Read 2 more answers
A weightlifter presses a 400 n weight 0.5 m over his head in 2 seconds, what is the power of the weight lifter
Scrat [10]
There are two ways to solve this problem. First we write the given.

Given: Force F = 400 N;  Height h = 0.5 m;  Time t = 2 s

Formula: P = W/t;  but Work W = Force x distance or W = f x d
 
Weight is also a Force, therefore:  W = mg, solve for Mass m = ?

m = w/g  m = 400 N/9.8 m/s²  m = 40.82 Kg

P = W/t = F x d/t  = mgh/t  P = (40.82 Kg)(9.8 m/s²)/2 s  

P = 100 J/s or 100 Watts

3 0
3 years ago
Other questions:
  • A baseball thrown from the outfield to home plate does not have which of the following types of energy while it's in the air? A.
    9·1 answer
  • What is the magnitude of the displacement of a car that travels half a lap along a circle of radius of 150m?
    6·1 answer
  • A 1170-kg car is held in place by a light cable on a very smooth (frictionless) ramp, as shown in the figure (Figure 1) . The ca
    13·1 answer
  • Compare the gravitational force on a 33 kg mass at the surface of the Earth (with ra-
    6·1 answer
  • Suppose you observe two stars and you know they have the same luminosity. If one star is twice as far away as the other, the mor
    15·1 answer
  • Please can i have help with this question ​
    12·1 answer
  • What is the relationship between the masses of the objects and the gravitational force between them
    10·1 answer
  • As longitudional waves travel, particles in the medium are pushed together and then pulled apart. We call this
    12·1 answer
  • Pls helpppppp i’ll give brainliest
    11·2 answers
  • The diagram below shows a 1.0 x 105newton truck at rest on a hill that makes an angle of 8.0° with the
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!