Answer: The specific heat capacity is very low.
Explanation:
The specific heat capacity of a body is defined as the heat energy required by a body to cause a unit change in its temperature. The value is over low that is why it is easier for the desert sand to easily get very hot during the day. Conversely, it is very easy for the desert sand to lose it's heat a cool breeze pass over it in the night making it very cold in the night. This value also defines how long the desert sand can retain heat. Therefore, the desert sand has a low specific heat capacity.
Answer:
I = 3.9 x 10⁷ W/m²
Explanation:
given,
Sheet of black paper dimension = 8.5 x 11 inch
Area of sheet = 8.5 x 11 = 93.5 inch^2
1 inch =0.0254 m
Area = 0.06032 m²
mass of sheet = 0.80 g
Force = m g = 0.8 x 9.8 x 10⁻³ N
= 7.84 x 10⁻³ N
speed of light = c = 3 x 10⁸ m/s
Using equation
where I is the intensity of light
I = 3.9 x 10⁷ W/m²
Intensity of the light is equal to I = 3.9 x 10⁷ W/m²
Answer:
<em>The canyon is approximately 314 meters away</em>
Explanation:
<u>Speed of Sound</u>
If we emit sounds in an open space where a large obstacle (like a mountain) is expected to return the sounds, then it will travel forth and back at a given speed for a certain time. We can assume the speed of sound is constant, so we could know the approximate distance of the mountain (or canyon in our case) by the known formula.
Where 
is the speed of sound and t is half the time we hear our echo.
The speed of sound in m/s can be calculated from the approximate formula in terms of the temperature T in degrees Celsius
We have 
, so
Let's compute x, for t=1.8/2=0.9 seconds
The canyon is approximately 314 meters away
Answer:
52,94N
Explanation:
Frictional force is the opposing force that is created between two surfaces that try to move in the same direction or that try to move in opposite directions. The main purpose of a frictional force is to create resistance to the motion of one surface over the other surface.
Calculation:
Le the value of frictional force be Fk, therefore acceleration a = (F- Fk)/m
where :
F is the applied force
m the mass of the cart
a = (F- Fk)/m = 0.8
F - Fk = 0.8m
Fk = F - 0.8m
Fk = 56.3 - (0.8×4.2)
Fk = 52.94 N
The magnitude, in Newtons, of the net frictional force is therefore 52.94N
