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2 years ago

g A ping pong ball (thin shell sphere) rolls down an incline at 30° from rest. What is its acceleration

Physics

1 answer:

Aleonysh [2.5K]2 years ago

3 0

Answer:

Explanation:

According to newtons second law of motion;

F = ma .... 1

Also the force acting aong the inclines is expressed as;

F = mgsintheta

m is the mass of the object

a is the acceleration

theta is angle of inclination

Equate 1 and 2

ma = mg sin theta

a = gsin(theta)

a = 9.8sin30

a = 9.8(0.5)

a = 4.9m/s²

Hence the acceleration of the ping pong is 4.9m/s²

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