Answer:
Explanation:
Let T be the tension
For linear motion of hoop downwards
mg -T = ma , m is mass of the hoop . a is linear acceleration of CG of hoop .
For rotational motion of hoop
Torque by tension
T x R , R is radius of hoop.
Angular acceleration be α,
Linear acceleration a = α R
So TR = I α
= I a / R
a = TR² / I
Putting this value in earlier relation
mg -T = m TR² / I
mg = T ( 1 + m R² / I )
T = mg / ( 1 + m R² / I )
mg / ( 1 + R² / k² )
Tension is less than mg or weight because denominator of the expression is more than 1.
Answer:
1066.67 m
Explanation:
Given:
v₀ = 96 km/h = 26.67 m/s
v = 48 km/h = 13.33 m/s
Δx = 800 m
Find: a
v² = v₀² + 2aΔx
(13.33 m/s)² = (26.67 m/s)² + 2a (800 m)
a = -0.333 m/s²
Given:
v₀ = 26.67 m/s
v = 0 m/s
a = -0.333 m/s²
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (26.67 m/s)² + 2 (-0.333 m/s²) Δx
Δx = 1066.67 m
Round as needed.
Aperture is measured in F-stops, in which the f-stops is the amount of light allowed to pass through the aperture, which simply put means that the smaller the aperture, the higher the f-stops. What it does is reduce the amount of light that reaches the film, so the higher the f-stops, the less light reaches the film.
R=u^2 sin2x / g
7.8=u^2 sin2*30 /10
u=9.5m/s
