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vredina [299]
3 years ago
7

An evaluation of R was performed, following the procedure described in this module. The barometric pressure was 736 torr, the te

mperature was 295k and volume of hydrogen gas collected was 35.6 mL. The calculated value of R was 82.1 mL atm K-1 mol-1.
1) How many grams of Magnesium metal were used?

2) If the vapor pressure of water had not been taken into account, what would have been the calculated value of R?

3) If the springe volume had been incorrectly read, giving a calculated system volume of 25.6 mL, what would have been the percent error in the calculated value of R?

Chemistry
1 answer:
Misha Larkins [42]3 years ago
6 0

mass of mg = 0.035g

calculated R value is less

percentage error = 71.91%


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Stable nuclei with low atomic numbers, up to 20, have a neutron to proton ratio of approximately ________.
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1 to 1. Most small atoms have the same number of protons and neutrons
6 0
3 years ago
A gas sample occupies 350.0 mL at 546 mm Hg. What volume does the gas occupy at 652 mm Hg?​
leva [86]

Answer:

293.1 mL.

Explanation:

  • Boyle's law states that: at a constant temperature the pressure of a given mass of an ideal gas is inversely proportional to its volume.
  • It can be expressed as: <em>P₁V₁ = P₂V₂,</em>

P₁ = 546.0 mm Hg, V₁ = 350.0 mL.

P₂ = 652.0 mm Hg, V₂ = ??? mL.

<em>∴ V₂ = (P₁V₁)/(P₂)</em> = (546.0 mm Hg)(350.0 mL) / (652.0 mm Hg) = <em>293.1 mL.</em>

8 0
3 years ago
Can someone help me, please?
DENIUS [597]
The answer to this question is: B) 3+
7 0
3 years ago
Read 2 more answers
If the volume occupied by the air in a bicycle pump is 525 cm3, and the pressure changes from 73.2 kPa to 122.5 k.Pa as the pist
Musya8 [376]

Answer:

V_2=313.71\ cm^3

Explanation:

Given that,

Initial volume, V_1=525\ cm^3

The pressure changes from 73.2 kPa to 122.5 k.Pa.

We need to find the new volume occupied by the air. Let it is V₂. It can be calculated using Boyle's law such that,

P_1V_1=P_2V_2\\\\V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{73.2\times 525}{122.5}\\\\V_2=313.71\ cm^3

So, the new volume is 313.71\ cm^3.

6 0
2 years ago
Problem Page Suppose 25.1g of barium nitrate is dissolved in 200.mL of a 0.50 M aqueous solution of ammonium sulfate. Calculate
melomori [17]

Answer:

1.26 M

Explanation:

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137 + 2x(14 + 3x16) = 199 g/mol

The number of moles is the mass divided by the molar mass, so:

n = 25.1/199 = 0.126 mol of Ba(NO₃)₂

In 1 mol of the salt, there are 2 moles of NO₃⁻, so the number of moles of nitrate is 0.252 mol. Nitrates formed with ammonium (that can react when the solid dissolves) and with elements from group 1 and 2 are completely soluble in water. So, the moles of nitrate will remain 0.252 mol.

The molarity is the number of moles divided by the volume (0.2 L):

[NO₃⁻]= 0.252/0.2 = 1.26 M

3 0
3 years ago
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